Can anyone please give me easy explanation for this?
Cindy has her eye on a sundress but thinks it is too expensive. It goes on sale for 15% less than the original price. Before Cindy can buy the dress, however, the store raises the new price by 25%. If the dress cost $68 after it went on sale for 15% off, what is the difference between the original price and the final price?
A) $0.00
B) $1.00
C) $3.40
D) $5.00
E) $6.80
OA: D
Percentage problem
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Original price = x
15% less = 85x/100
Further in the question it is stated that 85x/100 = 68 => x = 80 (Original Price)
Price again raised by 25% on 68. Therefore new price 85
New Price (85) - Original Price (80) = 5 Answer D.
15% less = 85x/100
Further in the question it is stated that 85x/100 = 68 => x = 80 (Original Price)
Price again raised by 25% on 68. Therefore new price 85
New Price (85) - Original Price (80) = 5 Answer D.
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15% discount = 15/100 = 3/20.pradeepfriend2000 wrote: Cindy has her eye on a sundress but thinks it is too expensive. It goes on sale for 15% less than the original price. Before Cindy can buy the dress, however, the store raises the new price by 25%. If the dress cost $68 after it went on sale for 15% off, what is the difference between the original price and the final price?
A) $0.00
B) $1.00
C) $3.40
D) $5.00
E) $6.80
The denominator here implies that the original price is almost certainly a multiple of 20 just a bit greater than the discounted price.
Since the discounted price = 68, the original price is probably 80:
80 less 3/20 = 80 - (3/20)80 = 80-12 = 68.
Success!
Discounted price increased by 25% = 68 + (1/4)68 = 68 + 17 = 85.
Difference between the final price and the original price = 85-80 = 5.
The correct answer is D.
Algebraically:
Since the 15% discount is equal to 3/20 of the original price, the discounted price is equal to 17/20 of the original price:
68 = (17/20)x
x = 68(20/17) = 80.
Discounted price increased by 25% = 68 + (1/4)68 = 68 + 17 = 85.
Difference between the final price and the original price = 85-80 = 5.
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
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