Which of the following represents the range of all possible

This topic has expert replies
Master | Next Rank: 500 Posts
Posts: 116
Joined: Sun May 22, 2011 1:11 am
Thanked: 7 times
If −3<x<5 and −7<y<9, which of the following represents the range of all possible values of y−x?
a. −4<y−x<4
b. −2<y−x<4
c. −12<y−x<4
d. −12<y−x<12
e. 4<y−x<12

In the solution provided for correct ans D,the max value of y is taken as 9 whereas the min value of x is taken as -3.Is this a mistake in the question or we can ignore < and consider it as <= ?

Senior | Next Rank: 100 Posts
Posts: 73
Joined: Sun May 06, 2012 2:19 am
Location: Cape Town
Thanked: 6 times

by rintoo22 » Thu Mar 28, 2013 5:39 am
-7<y<9 ..... 1
-3<x<5 ..... 2
------------------
-4<y-x<4

So the correct answer in my opinion should be a.
They have asked for range and not the maxim or minimum value.

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 511
Joined: Wed Aug 11, 2010 9:47 am
Location: Delhi, India
Thanked: 344 times
Followed by:86 members

by Anju@Gurome » Thu Mar 28, 2013 5:41 am
shreerajp99 wrote:... the max value of y is taken as 9 whereas the min value of x is taken as -3.Is this a mistake in the question or we can ignore < and consider it as <= ?
No this is not a mistake.
It is equivalent to saying that y can be as large as 8.999999..., i.e. just less than 9 and x can be as small as -2.99999..., i.e. just more than -3. Hence, we can always write (y - x) will be always less than (9 - (-3)) = 12

Similarly, (y - x) will be always greater than (-7 - 5) = -12

Note that we are never using ≤ instead of <, we are just hypothetically assuming the maximum/minimum value as we'll never be able to write the actual maximum or minimum value.

Hence, the correct answer is D.
Anju Agarwal
Quant Expert, Gurome

Backup Methods : General guide on plugging, estimation etc.
Wavy Curve Method : Solving complex inequalities in a matter of seconds.

§ GMAT with Gurome § Admissions with Gurome § Career Advising with Gurome §

Junior | Next Rank: 30 Posts
Posts: 27
Joined: Sat Feb 16, 2013 2:27 am
Location: India
Thanked: 1 times

by beatthe800 » Thu Mar 28, 2013 5:44 am
There seems to be no mistake found in q. [spoiler]"D"[/spoiler] is the only option which gives you range. All remaining options wont give proper result. You must be agree High(Y) is 8 and min(X) is -2 So (Y-X)= 10 . Which eliminates options A, B and C.
Now for lower bound: min(Y)=-6 and max(X)=4 So (Y-X) =-10
which eliminates option E.
Now you left with only one option, which is your answer.

Thanks,
beatthe800

User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pm
Location: New York, NY
Thanked: 13060 times
Followed by:1906 members
GMAT Score:790

by GMATGuruNY » Thu Mar 28, 2013 6:27 am
shreerajp99 wrote:If −3<x<5 and −7<y<9, which of the following represents the range of all possible values of y−x?
a. −4<y−x<4
b. −2<y−x<4
c. −12<y−x<4
d. −12<y−x<12
e. 4<y−x<12
To determine the lower limit and the upper limit of y-x, calculate y-x using every combination of endpoints (-7 and 9 for y, -3 and 5 for x):
-7-(-3) = -4.
-7-5 = -12.
9-(-3) = 12.
9-5 = 4.

The LOWER limit is the LEAST of the results above: -12.
The UPPER limit is the GREATEST of the results above: 12.
Thus:
-12 < y-x < 12.

The correct answer is D.

An alternate approach is to compare the answer choices and use process of elimination.

A, B and C indicate that y-x < 4.
D and E indicate that y-x < 12.
Try to plug in a combination of values such that y-x is BETWEEN 4 and 12.
If y=8 and x=-2, then y-x = 8-(-2) = 10.
Since it's possible that y-x > 4, eliminate A, B and C.

D indicates that y-x > -12.
E indicates that y-x > 4.
Try to plug in a combination of values such that y-x is BETWEEN -12 and 4.
If y=-6 and x=4, then y-x = -6-4 = -10.
Since it's possible that y-x < 4, eliminate E.

The correct answer is D.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3

Senior | Next Rank: 100 Posts
Posts: 89
Joined: Wed Mar 13, 2013 3:36 am
Thanked: 10 times
Followed by:1 members

by killerdrummer » Thu Mar 28, 2013 8:55 am
Hey shreerajp99 try this Quick and easy approach (without substitutions)

Given : -3<x<5 and -7<y<9
To find : y - x

Solution :
y-x = y + (-x)
Now we know the range of x is -3<x<5
Multiply by -1 and we get -5<-x<3

add the above with -7<y<9

-12<y-x<12... and we are done!! :)

Hope this helps.

Senior | Next Rank: 100 Posts
Posts: 48
Joined: Thu Jan 19, 2012 10:16 pm
Thanked: 2 times

by whats_in_the_store » Fri Mar 29, 2013 4:26 am
hey killerdrummer, that's awesome!

Senior | Next Rank: 100 Posts
Posts: 89
Joined: Wed Mar 13, 2013 3:36 am
Thanked: 10 times
Followed by:1 members

by killerdrummer » Mon Apr 29, 2013 8:52 am
Thanks Mate aka "whats_in_the_store"!! :)