Problem Solving

343. Mark is playing poker at a casino. Mark starts playing with 140 chips, 20% of which are $100 chips and 80% of which are $20 chips. For his first bet, Mark places chips, 10% of which are $100 chips, in the center of the table. If 70% of Mark's remaining chips are $20 chips, how much money did Mark bet?
A. $1,960
B. $1,740
C. $1,540
D. $3,080
E. $2,640

Need to rush for a party, so just posting the final eqn..

70/100(140-x) = 112 - 0.9*x .. Solving we get x = 70 ( x represents the number of chips he bet)

Of these 10% are $100 and 90% are $20 , so Value of bet = (10% of 70) * (100) + (90% of 70) * (20) = 1960.

Answer A.

Sorry for not writing all down!!!

Answer ia option A.

Once dealt at a very heavy roulette action casino.
Was struggling with large straight up bets...i.e 16 straight up had a dealer give me a shortcut it was awesome!!!
any straight up bet cut in half x 7 add a zero this is the payout.
example 12 straight up half of 12 is 6 x 7 is 42 add zero pays 420..64 straight up half is 32 x7 is 2240. and yes i had a guy bet 59 chips straight up on 17 and yes i did hit it...floor person was wrong on payout and pissed.i however got a nice tip 100.00... cause i rounded up to 60 by half is 30 which is 2100 minus 35 pays 2065.....impressed casino director too!!!