2^x - 2^(x-2) = 3(2^13) what is x?
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2^(x - 2) = (2^x)*(2^(-2)) = (2^x)/(2^2)kunalkulkarni wrote:2^x - 2^(x-2) = 3(2^13) what is x?
--> (2^x) - 2^(x - 2) = 3*(2^13)
--> (2^x) - (2^x)/(2^2) = 3*(2^13)
--> (2^2)*(2^x) - (2^x) = 3*(2^13)*(2^2)
--> (2^x)*[(2^2) - 1] = 3*(2^15)
--> 3*(2^x) = 3*(2^15)
Comparing the both sides, x = 15
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Another tricky method to solve this problem is to expressing the right side of the expression as powers of of 2 only so that we can compare it with the left side.
3*(2^13) = (4 - 1)*(2^13) = (2^2 - 1)(2^13) = 2^15 - 2^13 = 2^15 - 2^(15 - 2)
hence, x = 15
3*(2^13) = (4 - 1)*(2^13) = (2^2 - 1)(2^13) = 2^15 - 2^13 = 2^15 - 2^(15 - 2)
hence, x = 15
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We can plug in the answer choices for x.If 2^x - 2^(x-2) = 3(2^13), what is the value of x?
a) 9
b) 11
c) 13
d) 15
e) 17
Answer choice C: x= 13
2^13 - 2^(13-2) = 3(2^13)
2^13 - 2^11 = 3(2^13)
2^11(2^2 - 1) = 3(2^13)
2^11(3) = 3(2^13)
Plugging in x=13 made the exponent on the left 2^11.
To match 2^13 on the right side of the equation, the exponent needs to be increased by 2.
Thus, x = 13+2 = 15.
The correct answer is D.
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Thank you Anurag. The solution is awesome!
@Mitch: I kind of get excited when I see such challenging questions, and almost forget the plug-in concept! I should keep reminding myself about plug-in strategy when I get excited the next-time
Thank you.
Cheers,
Kunal
@Mitch: I kind of get excited when I see such challenging questions, and almost forget the plug-in concept! I should keep reminding myself about plug-in strategy when I get excited the next-time
Thank you.
Cheers,
Kunal
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The most important thing when analyzing any GMAT problem is to ask yourself - what concept is being tested? And what is my goal? Always ask yourself these questions before diving in.
Here, we're clearly testing properties of exponents. So what do you know about variable exponents? Well, if you can set the bases equal, you can set the exponents equal. For example, \(3^x = 27\), then \(3^x = 3^3\), so x must equal 3.
In this problem, though, we're subtracting on the left side, and we have a different base on the other side. We know we can only compare the exponents if we express everything as multiplication. So your goal is - How do you get the left side to look like the right side? How do you turn subtraction into multiplication? Well, by factoring! Pull out the biggest common factor from both terms on the left side:
$$2^x-2^{x-2}=3\left(2^{13}\right)$$
$$2^{x-2}\left(2^2-1\right)=3\left(2^{13}\right)$$
$$2^{x-2}\left(4-1\right)=3\left(2^{13}\right)$$
$$2^{x-2}\left(3\right)=3\left(2^{13}\right)$$
$$2^{x-2}=2^{13}$$
$$x-2=13$$
$$x=15$$
Here, we're clearly testing properties of exponents. So what do you know about variable exponents? Well, if you can set the bases equal, you can set the exponents equal. For example, \(3^x = 27\), then \(3^x = 3^3\), so x must equal 3.
In this problem, though, we're subtracting on the left side, and we have a different base on the other side. We know we can only compare the exponents if we express everything as multiplication. So your goal is - How do you get the left side to look like the right side? How do you turn subtraction into multiplication? Well, by factoring! Pull out the biggest common factor from both terms on the left side:
$$2^x-2^{x-2}=3\left(2^{13}\right)$$
$$2^{x-2}\left(2^2-1\right)=3\left(2^{13}\right)$$
$$2^{x-2}\left(4-1\right)=3\left(2^{13}\right)$$
$$2^{x-2}\left(3\right)=3\left(2^{13}\right)$$
$$2^{x-2}=2^{13}$$
$$x-2=13$$
$$x=15$$
Ceilidh Erickson
EdM in Mind, Brain, and Education
Harvard Graduate School of Education
EdM in Mind, Brain, and Education
Harvard Graduate School of Education