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Statement 1 is not sufficient. Statement 2 tells us that 170 is the greatest common divisor of z and 170 -- in other words, it just tells you that z is divisible by 170. That is not sufficient either.
Combined, we know that z is divisible by both 3 and 170. So z must be divisible by the LCM of 3 and 170, which is 510. Since 100 < z < 1000, the only possible value of z is 510. So yes, the answer is C.
Combined, we know that z is divisible by both 3 and 170. So z must be divisible by the LCM of 3 and 170, which is 510. Since 100 < z < 1000, the only possible value of z is 510. So yes, the answer is C.
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