Num Props

This topic has expert replies
Master | Next Rank: 500 Posts
Posts: 215
Joined: Mon Apr 21, 2008 8:07 am

Num Props

by rosh26 » Sun Jun 22, 2008 5:29 pm
Thanks in advance!
Attachments
Gmat Prep 2 (2nd) - Num Props.doc
(63 KiB) Downloaded 100 times

Master | Next Rank: 500 Posts
Posts: 124
Joined: Mon May 19, 2008 1:12 pm
Thanked: 3 times

by Nycgrl » Sun Jun 22, 2008 5:48 pm
For mv<pv<0 either m and p or v is -ve

1st m<p if m &p are +ve then v has to be -ve but if v is -ve then it doesnt satisfy mv<pv<0>-12 therefore it doesnt satisfy the condition mv<pv<0> o-----sufff

2nd m<0 means m is -ve with tha same logic as in 1st statment vhas to be greater than 0-----suff

Master | Next Rank: 500 Posts
Posts: 215
Joined: Mon Apr 21, 2008 8:07 am

by rosh26 » Mon Jun 23, 2008 4:38 pm
Hi NYC Girl -

Could you explain Statement 1 again? where did mv<pv<0>-12 equation xome from??

"1st m<p if m &p are +ve then v has to be -ve but if v is -ve then it doesnt satisfy mv<pv<0>-12 therefore it doesnt satisfy the condition mv<pv<0> o-----sufff"

Thanks.

Master | Next Rank: 500 Posts
Posts: 124
Joined: Mon May 19, 2008 1:12 pm
Thanked: 3 times

by Nycgrl » Mon Jun 23, 2008 7:36 pm
1 statment says M<P

now let m & p be positive eg m=2 p=4 now to satisfy mv<pv<0 V has to be negative becauz if v is postive then mv &pv both will be greater than 0 let v be -3
mv =2*-3= -6
pv = 4*-3 = -8 again this doen't satisfy mv<pv<0>-8]

therefore M& p must be ngative

let m=-4 p= -2 (m<p)
Let v=3

mv = -8 , pv=-6 [-8<-6<0] therefore mv<pv<0

V has to be greater than 0