Can someone please show me how to do this question ?
Is x negative ?
(1) 2x > x^2
(2) x< 1
I thought the answer should be E according to the below strategy -
(1) x^2-2x < 0 = x(x-2) <0
So, that means either x < 0 or x < 2
which is insufficient as x could be 1 or any decimal like 1.5 ( as it doesn't say that x is integer )
(2) x <1
clearly x can be 0.5 or any other decimal so insufficient.
But, the answer is A. Can someone explain me ? Thank You
Is x negative ?
This topic has expert replies
Here is how I see it:
(1) 2x > x^2
The only number that satisfies this inequality is 1 (2 > 1). A negative number will not satisfy. For example: 2(-1) > (-1)^2 = -2 > 1...which is incorrect. Because the only number that satisfies is 1, then the answer is sufficient.
(2) x could equal 0 or a negative number, therefore this is insufficient.
Hope this helps!
(1) 2x > x^2
The only number that satisfies this inequality is 1 (2 > 1). A negative number will not satisfy. For example: 2(-1) > (-1)^2 = -2 > 1...which is incorrect. Because the only number that satisfies is 1, then the answer is sufficient.
(2) x could equal 0 or a negative number, therefore this is insufficient.
Hope this helps!
- GMATGuruNY
- GMAT Instructor
- Posts: 15539
- Joined: Tue May 25, 2010 12:04 pm
- Location: New York, NY
- Thanked: 13060 times
- Followed by:1906 members
- GMAT Score:790
The portion in red is not quite correct.Param800 wrote:Can someone please show me how to do this question ?
Is x negative ?
(1) 2x > x^2
(2) x< 1
I thought the answer should be E according to the below strategy -
(1) x^2-2x < 0 = x(x-2) <0
So, that means either x < 0 or x < 2
which is insufficient as x could be 1 or any decimal like 1.5 ( as it doesn't say that x is integer )
Here's the CRITICAL POINT approach:
2x > x²
x² - 2x < 0
x(x-2) < 0.
The CRITICAL POINTS are x=0 and x=2.
These are the only values where x(x-2) = 0.
To determine the range(s) where x(x-2) < 0, test one value to the left and one value to the right of each critical point.
x<0
Plug x=-1 into 2x > x²:
2(-1) > (-1)²
-2 > 1.
Doesn't work.
x<0 is not a viable range.
0<x<2
Plug x=1 into 2x > x²:
2(1) > 1²
2 > 1.
This works.
0<x<2 is a viable range.
x>2
Plug x=3 into 2x > x²:
2(3) > 3²
6 > 9.
Doesn't work.
x>2 is not a viable range.
0<x<2 is the only range that satisfies statement 1 -- sufficient information to determine that x is not negative.
The correct answer is A.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3