In the rectangular coordinate system, are the points (a, b) and (c, d) equidistant from the origin?
(1) a/b = c/d
(2) root(a^2) + root(b^2) = root(c^2) + root(d^2)
OA C
Manhattan
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Statement 1: a/b = c/dIn the rectangular coordinate system, are the points (a, b) and (c, d) equidistant from the origin?
(1) a/b = c/d
(2) √(a²) + √(b²) = √(c²) + √(d²)
If the equation is 1/2 = 1/2, then (1,2) and (1,2) are equidistant from the origin.
If the equation is 1/2 = 2/4, then (1,2) and (2,4) are not equidistant from the origin.
INSUFFICIENT.
Statement 2: √(a²) + √(b²) = √(c²) + √(d²)
√x² = |x|.
Rephrasing the statement, we get:
|a| + |b| = |c| + |d|.
If the equation is |0| + |2| = |0| + |2|, then (0,2) and (0,2) are equidistant from the origin.
If the equation is |0| + |2| = |1| + |1|, then (0,2) and (1,1) are not equidistant from the origin.
INSUFFICIENT.
Statements 1 and 2 combined:
Let a/b = c/d = k.
Then a=kb and c=kd.
Substituting a=kb and c=kd into |a|+|b| = |c|+|d|, we get:
|kb|+|b| = |kd|+|d|
(k+1)|b| = (k+1)|d|
|b| = |d|, implying that |a| = |c|.
Since the x values in (a,b) and (c,d) are equidistant from the origin, and the y values in (a,b) and (c,d) are equidistant from the origin, the two points are equidistant from the origin.
SUFFICIENT.
The correct answer is C.
One take-away:
To evaluate each statement ON ITS OWN, I plugged in values.
To evaluate the two statements COMBINED, I applied algebra.
Many DS problems are best solved with this approach.
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Distance between the point A (x,y) and the origin can be found by the formula: D = √(x² + y²)das.ashmita wrote:In the rectangular coordinate system, are the points (a, b) and (c, d) equidistant from the origin?
(1) a/b = c/d
(2) root(a^2) + root(b^2) = root(c^2) + root(d^2)
OA C
We have to find if √(a² + b²) = √(c² + d²) OR (a² + b²) = (c² + d²)
(1) a/b = c/d implies a = cx and b = dx for some integer so that x is not zero; NOT sufficient.
(2) √(a²) + √(b²) = √(c²) + √(d²)
|a| + |b| = |c| + |d|; NOT sufficient.
Combining (1) and (2), a = cx and b = dx
|a| + |b| = |c| + |d|
|cx| + |dx| = |c| + |d|
|x|(|c| + |d|) = |c| + |d|
|x| = 1
Now a = cx and b = dx, so |a| = |c| and |b| = |d|
Squaring the above equation, a² = c² and b² = d²
Adding the equations, we get a² + b² = c² + d²; SUFFICIENT.
The correct answer is C.
Anurag Mairal, Ph.D., MBA
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