Order of operation

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Order of operation

by hariharakarthi » Sat Oct 13, 2012 10:55 am
What is the value of 6/2(1+2)?
(a)1
(b)9

Note: Order of operations rule
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by Anurag@Gurome » Sat Oct 13, 2012 9:03 pm
hariharakarthi wrote:What is the value of 6/2(1+2)?
(a)1
(b)9

Note: Order of operations rule
6/2(1 + 2) = 6/2(3) = 6/6 = 1

The correct answer is [spoiler](a)[/spoiler].
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by hariharakarthi » Mon Oct 15, 2012 6:08 am
Anurag,

Thanks for the reply. I have a quick qn here.

Once the expression inside parantheses has been resolved/evaluated, then we can get rid of the parantheses. In that sense, is it correct to remove the parantheses once we done the evaluation here. i.e (1+2) => 3.
Then the problem becomes 6/2*3. eventually to 3*3 = 9. Is it my understandign correct here?

or

Whenever we encounter parantheses,the parantheses can only be removed by evaluating the expression inside it, if any, and doing the operation of evaluated expression with next variable availale in the expression.

Is the below order of operation rule correct?

The key to order of operaion is to follow an order, evaluating what is inside any parentheses before
moving on to exponents, which you must do before moving on to multiplication and division, which is followed by addition and subtraction. It does not matter whether you do multiplication before division or addition before subtraction.
Regards,
hhk