if X & Y are integer is X^7 is greater that 6^Y
1. X^3=-125
2. Y^2=36
whether the statement A/B alone is sufficient/both together is sufficient/insufficient
Data Sufficiency-if X & Y are integer
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given: x, y are integers
considering x^3 = -125
-> x = -5
x^7 = (-5)^7 = -ve number
6^y where y is any integer
take y = -2, 6^y is positive
y = 0, 6^y is positive
y = 2, 6^y is positive
so, x^3 is less than 6^y.
it is sufficient to answer.
consider y^2 = 36,
-> y = +6 or -6
we don`t have any information of x^7. so, it is not sufficient.
Hence, it is A alone is sufficient
considering x^3 = -125
-> x = -5
x^7 = (-5)^7 = -ve number
6^y where y is any integer
take y = -2, 6^y is positive
y = 0, 6^y is positive
y = 2, 6^y is positive
so, x^3 is less than 6^y.
it is sufficient to answer.
consider y^2 = 36,
-> y = +6 or -6
we don`t have any information of x^7. so, it is not sufficient.
Hence, it is A alone is sufficient
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If X and Y are integers. Is X^7 greater than 6^Y
X^7 = -5^7 = Negative number
6^Y = Positive number
-5^7 < 6^Y. So, statement I is sufficient to asnwer the question.
6^Y = 6^6 or 6^-6
X^7 = ?
If X is -10, then X^7 is less than 6^6 or 6^-6.
If X is 10, then X^7 is greater than 6^6 or 6^-6.
Since we don't have a definite answer, statement II is insufficient to answer the question.
IMO Option A is the correct answer choice.
X = -5.1. X^3=-125
X^7 = -5^7 = Negative number
6^Y = Positive number
-5^7 < 6^Y. So, statement I is sufficient to asnwer the question.
Y = -6 or 62. Y^2=36
6^Y = 6^6 or 6^-6
X^7 = ?
If X is -10, then X^7 is less than 6^6 or 6^-6.
If X is 10, then X^7 is greater than 6^6 or 6^-6.
Since we don't have a definite answer, statement II is insufficient to answer the question.
IMO Option A is the correct answer choice.
Anil Gandham
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Target question: Is x^7 > 6^y?CSASHISHPANDAY wrote:if X & Y are integer is X^7 is greater that 6^Y
1. X^3=-125
2. Y^2=36
Statement 1: x^3 = -125
There's a nice rule that says, "An odd exponent preserves the sign of the base"
In other words, (any negative number)^(odd integer) = negative number
. . . and (any positive number)^(odd integer) = positive number
So, statement 1 essentially tells us that x must be a negative number. Now, we could go further and determine that x = -5, but that's not really necessary here. Knowing that x is negative provides enough information to answer our target question with certainty.
First, since x is negative, we know that x^7 must be negative.
Second, we know 6^(any value) will equal a positive number.
So, it must be the case that Is x^7 is not greater than 6^y?
Statement 1 is SUFFICIENT
Statement 2: y^2 = 36
From this, we can conclude that y = 6 or y = -6.
Let's examine both cases:
case a: y = 6.
In this case, we cannot determine whether x^7 is greater than 6^y, since we have no idea what x equals.
case b: y = -6.
In this case, we cannot determine whether x^7 is greater than 6^y, since we have no idea what x equals.
Statement 2 is NOT SUFFICIENT
Answer = A
Cheers,
Brent
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