Tricky Square Root Problem - Expert help please

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This is from Manhattan Gmat challenge problem of the week:
https://www.beatthegmat.com/mba/2012/08/ ... ugust-2012


Rounded to four decimal places, the square root of the square root of 0.9984 is approximately

A. 0.9990
B. 0.9992
C. 0.9994
D. 0.9996
E. 0.9998




"Now we have the insight we need. Since the square of 1 - x is approximately 1 - 2x (doubling the gap between the number and 1) if x is very small, then we can go in the opposite direction: the square root of 1 - 2x is approximately 1 - x. In other words, you cut the gap between the number and 1 in half."

More specifically, above is the part of the explanation that I don't understand (not good considering this is the 'insight we need'). I don't understand how you get square root of (1-2x) roughly equals (1-x).




Answer

First, notice that the number you have to take the first square root of, 0.9984, is just a little less than 1, meaning that you could represent it as 1 - (something small).

Now, it's hard to deal with square roots algebraically. But we can deal with their opposites - that is, squares. What would the square of 1 - (something small) be? Let's write that as 1 - x, where we know that x is a small number, much less than 1.

(1-x)^2 = 1 - 2x - x^2

Now, since x is much less than 1, the term is much much less than 1. (To see why, imagine that x = 1/1,000. Then = 1/1,000,000.) Since we are rounding in this problem, we can make an approximation, dropping the term:

(1-x)^2 = 1- 2x - x^2 ≈ 1 - 2x

Now we have the insight we need. Since the square of 1 - x is approximately 1 - 2x (doubling the gap between the number and 1) if x is very small, then we can go in the opposite direction: the square root of 1 - 2x is approximately 1 - x. In other words, you cut the gap between the number and 1 in half.

Write 0.9984 as 1 - 0.0016. In this case, 2x = 0.0016, so x = 0.0008.

The square root of 1 - 0.0016 is approximately 1 - 0.0008, or 0.9992.

Take the final step. The square root of 1 - 0.0008 is approximately 1 - 0.0004, or 0.9996.

You could also get to the answer by working backwards from the answer choices: the square of the square of the right answer must be approximately 0.9984. It will take longer, but brute force will get you there, eventually.

The correct answer is D.
Last edited by allsaints921 on Wed Aug 29, 2012 8:08 am, edited 1 time in total.

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by adthedaddy » Wed Aug 29, 2012 7:22 am
In the answer, where the author is speaking on insight is about the "root-square interconversion & dropping the middle term while squaring the terms for 0<x<1"

When following example is mentioned in the question,
Now, since x is much less than 1, the term is much much less than 1. (To see why, imagine that x = 1/1,000. Then = 1/1,000,000.) Since we are rounding in this problem, we can make an approximation, dropping the term:

(1-x)^2 = 1- 2x - x^2 ≈ 1 - 2x
The above rule is applicable because 0<x<1.
When a number is between 0 & 1, its value decreases upon squaring. Thus x^2 <<< 2x, hence it can be ignored.

A rule is devised where-in sq.root of (1-2x) is approx. equal to (1-x) and vice versa.
i.e. cutting the gap betwn number and 1 into half.

So, you've to keep cutting the same for the given example.

Hope I am able to communicate it.
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by coolhabhi » Wed Aug 29, 2012 8:29 pm
allsaints921 wrote:More specifically, above is the part of the explanation that I don't understand (not good considering this is the 'insight we need'). I don't understand how you get square root of (1-2x) roughly equals (1-x).
(1-x)^2 = 1 - 2x - x^2 ≈ 1 - 2x

that is (1-x)^2 ≈ 1 - 2x
that means 1 - 2x ≈ (1-x)^2
Taking square root on both sides we have
sqrt (1 - 2x)≈ sqrt{(1-x)^2}
=>sqrt (1 - 2x)≈ (1-x)

Instead of writing all these steps the author has put it in words as
"Now we have the insight we need. Since the square of 1 - x is approximately 1 - 2x (doubling the gap between the number and 1) if x is very small, then we can go in the opposite direction: the square root of 1 - 2x is approximately 1 - x. In other words, you cut the gap between the number and 1 in half."

Hope you have understood. :)

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by Ian Stewart » Thu Aug 30, 2012 4:24 am
allsaints921 wrote: Rounded to four decimal places, the square root of the square root of 0.9984 is approximately

A. 0.9990
B. 0.9992
C. 0.9994
D. 0.9996
E. 0.9998
While the algebraic ingredients that go into solving this question are certainly relevant on the GMAT, you won't see a question quite like this one on the test. Almost no one would know the math required in advance of seeing this type of problem, and to work out the mathematical basis needed to make an estimate here would take almost anyone well more than 2 minutes. But I can offer a different presentation of the solution in case it helps:

It's easier to first try the reverse problem, and a simpler version of it too. Say you are asked to approximate (0.97)^2. You could do long multiplication, but say instead we rewrite 0.97 as 1 - 0.03, so we want to find (1 - 0.03)^2. From algebra, we know that (x - y)^2 is always equal to x^2 - 2xy + y^2. Applying that here:

(1 - 0.03)^2 = (1)^2 - (2)(1)(0.03) + (0.03)^2
= 1 - (2)(0.03) + (0.03)^2

Now in this last line, if you think about how large each term is, the last term, (0.03)^2, is minuscule compared to the other two (it's equal to 0.0009, so it's tiny even compared to the middle term above). So if we only need to estimate, we can ignore that term, and we find that 0.97^2 is roughly equal to 1 - (2)(0.03) = 0.94.

From there you can generalize: if x is *very* close to zero, then (1-x)^2 will be very close in value to 1 - 2x. The larger x is, the worse this estimate will be. And if it's true that (1 - x)^2 is roughly equal to 1 - 2x, then taking square roots, 1 - x should be roughly equal to √(1 - 2x) when x is close to 0.

So that's what they've used in this question. It's easy to apply this estimate quickly, if you have numbers, if you notice that 1-x is just going to be halfway between 1 and 1-2x. Since we know 1-x is roughly equal to √(1 - 2x), that means √(1 - 2x) is roughly halfway between 1 and 1-2x. So if we need to estimate, say, √0.9, we can get a good estimate by finding the number which is halfway between 0.9 and 1, so 0.95 will be very close to the right answer (the actual answer is, to a few decimal places, 0.9487, so this is a very good estimate).

So to estimate the square root of 0.9984, we can just find its midpoint with 1; we get 0.9992. The question asks us to take the square root twice, so we can repeat the process, and the midpoint of 0.9992 and 1 is just 0.9996, so that will be a good approximation of the answer.

All of that said, the wording of the question is simply bizarre. The question asks "Rounded to four decimal places, the square root of the square root of 0.9984 is approximately". That question doesn't make sense. Rounded to four decimal places, the answer is exactly 0.9996. We're not approximating anything after we round off to four decimal places. As the question is worded, every answer is correct, because every answer is "approximately" equal to what we're asked to find. A question can ask you to round, or it can ask you to approximate, but it can't do both.
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