If the perimeter of a regular hexagon is P, in terms of P, what is the length of the diagonals?
(A) P*root3/2
(B) P/3
(C) P*root3/3
(D) P/4
(E) P/6
ans :B
how do i solve this ?
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hexagon problem
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anjaligeorge1
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Ian Stewart
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In a regular hexagon ABCDEF, all angles are 120 degrees. Connect AD, BE and CF: you've divided the hexagon into six equilateral triangles (they must be equilateral, because you've divided each 120 degree angle exactly in half, so two angles in each triangle are certainly 60 degrees). Look at the line AD; from A to the centre of the hexagon is one side of one equilateral triangle, and from the centre to D is another side. Each side of each equilateral is as long as one side of the hexagon, and one side in the hexagon is P/6 in length, so AD, BE and CF are each 2*P/6 = P/3 in length.
Much easier to see if you draw the picture!
Much easier to see if you draw the picture!
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netigen
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There is another way to solve this, though not as efficient as pointed out in a previous post
Connect a diagonal, you get a isosceles trapezoid
draw perpendiculars connecting the two bases of the trapezoid to get two right angle triangle and one rectangle.
length of rectangle = side of hexagon = p/6
triangle is a 30-60-90 right angle triangle so the base will be (p/6) x 1/2 = p/12
add up to get = p/6+p/12+p/12 = p/3
I recently got a similar question in one of my PR tests. See the attachment.
Connect a diagonal, you get a isosceles trapezoid
draw perpendiculars connecting the two bases of the trapezoid to get two right angle triangle and one rectangle.
length of rectangle = side of hexagon = p/6
triangle is a 30-60-90 right angle triangle so the base will be (p/6) x 1/2 = p/12
add up to get = p/6+p/12+p/12 = p/3
I recently got a similar question in one of my PR tests. See the attachment.
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llewellyn27
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Easy way to solve this is by plugging in numbers
We know that a hexagon is made up of 6 Equilateral triangles
Assume s = length of 1 side
So perimeter = 6s
Let P= 36 (divisible by 6)
So s = 6
Diagonal is formed by the sides of 2 of the 6 Eq triangles in the figure
so Diagonal is 12
Input p =36 in the answer choices and you will find that p/3 = 12
We know that a hexagon is made up of 6 Equilateral triangles
Assume s = length of 1 side
So perimeter = 6s
Let P= 36 (divisible by 6)
So s = 6
Diagonal is formed by the sides of 2 of the 6 Eq triangles in the figure
so Diagonal is 12
Input p =36 in the answer choices and you will find that p/3 = 12
