If x + y + z > 0, is z > 1?
(1) z > x + y +1
(2) x + y + 1 < 0
need help in this DS
This topic has expert replies
-
- Junior | Next Rank: 30 Posts
- Posts: 12
- Joined: Tue May 20, 2008 6:05 pm
- Location: california
- Thanked: 1 times
-
- Master | Next Rank: 500 Posts
- Posts: 294
- Joined: Tue Feb 26, 2008 9:05 pm
- Thanked: 13 times
- Followed by:1 members
I think B is ans here.
Let's attack stem 2 here:
We are given (x+y+z) is positive. since >0
From stem : x+y+1<0
so, x+y<1>0
so sufficient !
From 1 :z>x+y+1 => x+y+1<z> x+y-z <1> x+y+z <2z> 2z-1 > 0
=> z > 1/2 not sufficient
Let's attack stem 2 here:
We are given (x+y+z) is positive. since >0
From stem : x+y+1<0
so, x+y<1>0
so sufficient !
From 1 :z>x+y+1 => x+y+1<z> x+y-z <1> x+y+z <2z> 2z-1 > 0
=> z > 1/2 not sufficient