A closed cylindrical tank contains 36Ï€ cubic feet of
water and is filled to half its capacity. When the tank
is placed upright on its circular base on level ground,
the height of the water in the tank is 4 feet. When the
tank is placed on its side on level ground, what is the
height, in feet, of the surface of the water above the
ground?
I did not quite understand the explanation given in teh book. Any thoughts on this please.
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- thephoenix
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volume of cyl=pi r^2 Hbecnil wrote:A closed cylindrical tank contains 36Ï€ cubic feet of
water and is filled to half its capacity. When the tank
is placed upright on its circular base on level ground,
the height of the water in the tank is 4 feet. When the
tank is placed on its side on level ground, what is the
height, in feet, of the surface of the water above the
ground?
I did not quite understand the explanation given in teh book. Any thoughts on this please.
now V=1/2(volume)=pi r^2 H/2=36
from here we r
now when the cylinder is laid down along the side
the height will be= dia of circlular base
since its half filled H=d/2=r
HTH
- ajith
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The volume of cylindrical tank = π *r^2*hbecnil wrote:A closed cylindrical tank contains 36π cubic feet of
water and is filled to half its capacity. When the tank
is placed upright on its circular base on level ground,
the height of the water in the tank is 4 feet. When the
tank is placed on its side on level ground, what is the
height, in feet, of the surface of the water above the
ground?
I did not quite understand the explanation given in teh book. Any thoughts on this please.
now h = 4
Volume = 36Ï€
r^2 = Volume/Ï€*h = 36Ï€/4Ï€ = 9
r= 3 feet
The tank has a height of 8 feet (it is mentioned that tank is only half filled) and it is half full
So if it is kept on sides, it will be filled till half of the diameter
Diameter = 6 feet, the tank will be filled till 3 feet
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- prateek_guy2004
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Its simple...
What given Volume = 36
Height = 4ft
Volume = Pi* r2 * h
36 = Pi*r2 * 4
r2 =9
r = 3
So the radius is 3 which means the diameter is 6.
This is what the ques asked.
What given Volume = 36
Height = 4ft
Volume = Pi* r2 * h
36 = Pi*r2 * 4
r2 =9
r = 3
So the radius is 3 which means the diameter is 6.
This is what the ques asked.
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why is the height = 4?
i thought the height is 8, since the height of the water is the tank is 4 feet when the tank is filled to half its capacity:
r^2 * pi * 8 = 36 * pi
could anybody explain plz?
i thought the height is 8, since the height of the water is the tank is 4 feet when the tank is filled to half its capacity:
r^2 * pi * 8 = 36 * pi
could anybody explain plz?
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ah i think i got it now! the phrase "... is filled to half its capacity" is needless to calculate r. the tank is half full, and this equals 36 * piFractal wrote:why is the height = 4?
i thought the height is 8, since the height of the water is the tank is 4 feet when the tank is filled to half its capacity:
r^2 * pi * 8 = 36 * pi
could anybody explain plz?
i misinterpreted the text...
In my version of the book, the question is given as:
A closed cylindrical tank contains 36Ï€ cubic feet of water and is filled to half its capacity. When the tank is placed upright on its circular base on level ground, the height of the water in the tank is 2 feet. When the tank is placed on its side on level ground, what is the height, in feet, of the surface of the water above the ground?
(A) 2
(B) 3
(C) 4
(D) 6
(E) 9
Note the height of the water has changed.
This is how I attempted to solve the problem:
V = h x πr2
Total volume of container, since it is half full, would be 72Ï€
72π = 4 x πr2
18 = r2
square root 18 = r
Therefore, when the tank is placed on its side, shouldn't the height of the water be the square root of 18?
A closed cylindrical tank contains 36Ï€ cubic feet of water and is filled to half its capacity. When the tank is placed upright on its circular base on level ground, the height of the water in the tank is 2 feet. When the tank is placed on its side on level ground, what is the height, in feet, of the surface of the water above the ground?
(A) 2
(B) 3
(C) 4
(D) 6
(E) 9
Note the height of the water has changed.
This is how I attempted to solve the problem:
V = h x πr2
Total volume of container, since it is half full, would be 72Ï€
72π = 4 x πr2
18 = r2
square root 18 = r
Therefore, when the tank is placed on its side, shouldn't the height of the water be the square root of 18?
A closed cylindrical tank contains 36Ï€ cubic feet of
water and is filled to half its capacity. When the tank
is placed upright on its circular base on level ground,
the height of the water in the tank is 2 feet. When the
tank is placed on its side on level ground, what is the
height, in feet, of the surface of the water above the
ground?
I did not quite understand the explanation given in teh book. Any thoughts on this please.
my book says the same thing, and I was confused as well!
water and is filled to half its capacity. When the tank
is placed upright on its circular base on level ground,
the height of the water in the tank is 2 feet. When the
tank is placed on its side on level ground, what is the
height, in feet, of the surface of the water above the
ground?
I did not quite understand the explanation given in teh book. Any thoughts on this please.
my book says the same thing, and I was confused as well!
I have this same issue with the problem. The problem CLEARLY states that "A closed cylindrical tank contains 36Ï€ cubic feet of water" and you are told that the tank is only half full. So that would mean that the total volume of the tank is 72Ï€, but no, they say that the volume is 36Ï€ and thus the volume of the water within the tank is 18Ï€.Rainy wrote:In my version of the book, the question is given as:
A closed cylindrical tank contains 36Ï€ cubic feet of water and is filled to half its capacity. When the tank is placed upright on its circular base on level ground, the height of the water in the tank is 2 feet. When the tank is placed on its side on level ground, what is the height, in feet, of the surface of the water above the ground?
(A) 2
(B) 3
(C) 4
(D) 6
(E) 9
Note the height of the water has changed.
This is how I attempted to solve the problem:
V = h x πr2
Total volume of container, since it is half full, would be 72Ï€
72π = 4 x πr2
18 = r2
square root 18 = r
Therefore, when the tank is placed on its side, shouldn't the height of the water be the square root of 18?
They should have stated that the volume of the tank was 36Ï€, not that the volume of the water within the tank is 36Ï€.