Hi All--
I find this absolute problem confusing--it seems nonsensical to me. Can someone help?
if Y>=0, what is the value of X?
1. |x-3|>=Y
2. |x-3|<=-Y
Thanks!
Confusing Absolute Value Q
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Any function inside a modulus is always +ve.
We are given y is 0 or +ve.
Statement 1:
|x-3| is ALWAYS +ve. We're given 'y' is +ve as well. X and Y can have infinite values - Insufficient.
Statement 2:
Again we know |x-3| is +ve. Since 'y' is +ve or 0. LHS will be -ve or 0. (the '-Y' term)
'-Y' CANNOT be -ve as the RHS is always +ve, so it HAS to be 0.
|X-3| = 0 -> X = 3 (Sufficient) B IMO
We are given y is 0 or +ve.
Statement 1:
|x-3| is ALWAYS +ve. We're given 'y' is +ve as well. X and Y can have infinite values - Insufficient.
Statement 2:
Again we know |x-3| is +ve. Since 'y' is +ve or 0. LHS will be -ve or 0. (the '-Y' term)
'-Y' CANNOT be -ve as the RHS is always +ve, so it HAS to be 0.
|X-3| = 0 -> X = 3 (Sufficient) B IMO
- neelgandham
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If y>=0, what is the value of X?
The value of -y is <0. (as y > 0, i.e. -y < 0)
So |x-3| cannot be < y but can only be equal to y at y = 0
x-3 = 0; x =3
Sufficient !
IMO B
Implies x-3 >y or x-3 <-y, Insufficient(too many values)1. |x-3|>=Y
The value of |x-3| is > 02. |x-3|<=-Y
The value of -y is <0. (as y > 0, i.e. -y < 0)
So |x-3| cannot be < y but can only be equal to y at y = 0
x-3 = 0; x =3
Sufficient !
IMO B
Anil Gandham
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