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by dev.gavande » Sun Nov 06, 2011 10:58 pm
If x-b^1/3 = c^6, then x=

1) c^2 + b
2) c^6 + b
3) c^9 + b
4) c^12 + b
5) c^18 + b

Help !

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by neelgandham » Mon Nov 07, 2011 12:58 am
Cubic Root(x-b) = c^6 then X= ?

x-b = c^18
x = b+c^18

IMO E

Already answered here : https://www.beatthegmat.com/cube-root-t94865.html
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by gmatblood » Mon Nov 07, 2011 12:59 am
dev.gavande wrote:If x-b^1/3 = c^6, then x=

1) c^2 + b
2) c^6 + b
3) c^9 + b
4) c^12 + b
5) c^18 + b

Help !
Is it (x-b)^1/3 ??

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by dev.gavande » Mon Nov 07, 2011 3:03 am
@gmatblood : Yes