1. In how many ways can 5 rings be worn on the four fingers of the right hand?
2. Three math books, four english books, and four reasoning books are kept on a shelf. In how many ways can they be arranged so that the books of each type are always together?
3. How many 3 letter words can be constructed using all the 26 letters of the english alphabet if only the middle letter of each word is a vowel?
4. In how many ways can 5 identical black balls and 7 identical white balls be arranged in a row so that no 2 black balls are together?
5. In how many ways can all the 7 sweets be distributed to three friends Jack, Jill, and John so that Jill alway sgets 2 sweets and each of them gets at least one sweet?
6. In how many ways can 4 men and 4 women sit at a round table with no two women in a consectuive position?
7. In how many ways can one choose 6 cards from a normal deck of cards so as to have all suits present?
Few more permutations/combination questions
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- cans
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Assuming one finger can have all the 5 rings: 4^5. (4*4*4*4*4)1. In how many ways can 5 rings be worn on the four fingers of the right hand?
2. Three math books, four english books, and four reasoning books are kept on a shelf. In how many ways can they be arranged so that the books of each type are always together?
3!*3!*4!*4!
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3. How many 3 letter words can be constructed using all the 26 letters of the english alphabet if only the middle letter of each word is a vowel?
for the middle letter: 5 options.
21 consonants.
21*5*21 (its not mentioned that letters can't be repeated)
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4. In how many ways can 5 identical black balls and 7 identical white balls be arranged in a row so that no 2 black balls are together?
arrange 7 white balls: 1 way.
no. of gaps = 8
pick any 5 spaces and put black balls. 8C5.
Arrange them:1
thus 8C5
7C2 (for Jill) * (2^5 - 1 -1) (2^5 because each of the sweet can be given to any of the 2 persons.5. In how many ways can all the 7 sweets be distributed to three friends Jack, Jill, and John so that Jill alway sgets 2 sweets and each of them gets at least one sweet?
-1 and -1 because in case all the sweets given to only Jack or to only John)
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6. In how many ways can 4 men and 4 women sit at a round table with no two women in a consectuive position?
arrange 4 men: 3! (round table)
Now 4 spaces and 4 women: 4!
3!*4!
13^4 * 48C27. In how many ways can one choose 6 cards from a normal deck of cards so as to have all suits present?
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why do you do that for #2? how do you come up with your answers ?cans wrote:Assuming one finger can have all the 5 rings: 4^5. (4*4*4*4*4)1. In how many ways can 5 rings be worn on the four fingers of the right hand?
2. Three math books, four english books, and four reasoning books are kept on a shelf. In how many ways can they be arranged so that the books of each type are always together?
3!*3!*4!*4!
- cans
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as books of each type are together, let bundle be: M,E,R.fangtray wrote:why do you do that for #2? how do you come up with your answers ?cans wrote:Assuming one finger can have all the 5 rings: 4^5. (4*4*4*4*4)1. In how many ways can 5 rings be worn on the four fingers of the right hand?
2. Three math books, four english books, and four reasoning books are kept on a shelf. In how many ways can they be arranged so that the books of each type are always together?
3!*3!*4!*4!
Thus 3! ways to arrange the bundles.
Now internally in the bundles, the books can be arranged.
Maths 3! and so on...
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- arslanoqads
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hey cans, are you considering the sweets different in question 5?cans wrote:4. In how many ways can 5 identical black balls and 7 identical white balls be arranged in a row so that no 2 black balls are together?
arrange 7 white balls: 1 way.
no. of gaps = 8
pick any 5 spaces and put black balls. 8C5.
Arrange them:1
thus 8C5
7C2 (for Jill) * (2^5 - 1 -1) (2^5 because each of the sweet can be given to any of the 2 persons.5. In how many ways can all the 7 sweets be distributed to three friends Jack, Jill, and John so that Jill alway sgets 2 sweets and each of them gets at least one sweet?
-1 and -1 because in case all the sweets given to only Jack or to only John)