If m and n are both two-digit numbers, and m-n = 11x, is x an integer?
(1) The tens digit and the units digit of m are the same.
(2) m + n is a multiple of 11.
I got caught up in thinking that a two digit number could be an integer like 12 or 99 or a decimal like 1.2? Can a two digit number, as this stimulus provides for be two digits separated by a decimal point?
Can a two digit number contain a decimal point?
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It clearly states that m and n are 2 digit numbers. You cannot include decimal numbers unless
otherwise stated
m-n=11x.
Statement 1
m=22,33,44,55..99 ;
22-11x=n
11(2-x)=n. Therefore x=1. Sufficient
Statement 2
m+n = 11k , where k is a positive integer
From the prompt m-n=11x
2m = 11(k+x). In order for m to be a 2 digit integer, x has to be an integer. Sufficient
otherwise stated
m-n=11x.
Statement 1
m=22,33,44,55..99 ;
22-11x=n
11(2-x)=n. Therefore x=1. Sufficient
Statement 2
m+n = 11k , where k is a positive integer
From the prompt m-n=11x
2m = 11(k+x). In order for m to be a 2 digit integer, x has to be an integer. Sufficient
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when 2 digit number is mentioned, it means without decimal...
A) m=99, n=11 true and if n=12, not true. insufficient
B) m+n is multiple of 11. m=12 and n=21 not true, m=11 and n=11, true.
Insufficient
A&B) m is multiple of 11 and m+n also. thus n is also multiple of 11. or m-n is also
IMO C
A) m=99, n=11 true and if n=12, not true. insufficient
B) m+n is multiple of 11. m=12 and n=21 not true, m=11 and n=11, true.
Insufficient
A&B) m is multiple of 11 and m+n also. thus n is also multiple of 11. or m-n is also
IMO C
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