The number of stamps that Kaye and Alberto had were in the ratio 5:3, respectively. After Kaye gave Alberto 10 of her stamps, the ratio of the number Kaye had to the number Alberto had was 7:5. As a result of this gift, Kaye had how many more stamps than Alberto?
a) 20
b) 30
c) 40
d) 60
e) 90
[spoiler]Answer: C[/spoiler]
Can someone please explain how to solve?
Ratios Problem
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Let the Initial number of stamps of Kaye and Alberto be 5a and 3a , ratio of stamps with Kaye & Alberto is 5a /3aneoshichhadva wrote:The number of stamps that Kaye and Alberto had were in the ratio 5:3, respectively. After Kaye gave Alberto 10 of her stamps, the ratio of the number Kaye had to the number Alberto had was 7:5. As a result of this gift, Kaye had how many more stamps than Alberto?
a) 20
b) 30
c) 40
d) 60
e) 90
[spoiler]Answer: C[/spoiler]
Can someone please explain how to solve?
Now , Kaye gave Alberto 10 of her stamps, the ratio of the number Kaye had to the number Alberto had was 7:5
So , 5a - 10 /3a + 10 = 7/5
25a - 50 = 21a + 70
4a = 120
So , a = 30
So initially Kaye gave Alberto had , 150 and 90 stamps....
Later , Kaye gave Alberto 10 of her stamps
So stamps with Kaye and Alberto after giving 10 stamps is :
Kaye : 140
Alberto : 100
So difference between them is 140 -100 = 40 stamps...
Option C.
Abhishek
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5x and 3x initially.
5x-10 / 3x+10 = 7/5
25x-50 = 21x + 70
x=30
thus final: 140 and 100
140-100=40
IMO C
5x-10 / 3x+10 = 7/5
25x-50 = 21x + 70
x=30
thus final: 140 and 100
140-100=40
IMO C
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Kalye/Alberto = 5X/3X
After, Kayle gives Alberto 10 of her stamps,
ratio becomes - 5X-10/(3X+10) = 7/5 (New ratio given)
Solve for X; we get X=30.
Therefore; Stamps Kayle has = 5X-10 = 140
Alberto = 3X+10 = 100
Difference = 40
After, Kayle gives Alberto 10 of her stamps,
ratio becomes - 5X-10/(3X+10) = 7/5 (New ratio given)
Solve for X; we get X=30.
Therefore; Stamps Kayle has = 5X-10 = 140
Alberto = 3X+10 = 100
Difference = 40