How many people came

This topic has expert replies
User avatar
Master | Next Rank: 500 Posts
Posts: 158
Joined: Wed Jun 16, 2010 8:21 am
Thanked: 13 times
Followed by:1 members

How many people came

by rohit_gmat » Sun Sep 11, 2011 7:56 am
Q. If everyone was charged the same fee, how many people came?
A. If the fee had been %0.75 less and 100 more people came, the club would have received the same amount.
B. If fee had been $1.50 more and 100 fewer people came, the club would have received the same amount.

source : 198 700+ Qs list

OA : C
IMO : A

plz provide explanations as well.. thanks !! :)

User avatar
Legendary Member
Posts: 1309
Joined: Mon Apr 04, 2011 5:34 am
Location: India
Thanked: 310 times
Followed by:123 members
GMAT Score:750

by cans » Sun Sep 11, 2011 8:54 am
n people came. fees = f.. fee received = fn
A) (f- f/7500)(n+100) = fn
insufficient.
B) (f+1.5)(n-100)=fn -> 1.5n -100f -150=0.
3n - 200f - 300 =0 insufficient.
combining A,B we have 2 eqn and 2 variable. Thus IMO C
If my post helped you- let me know by pushing the thanks button ;)

Contact me about long distance tutoring!
[email protected]

Cans!!

User avatar
Master | Next Rank: 500 Posts
Posts: 158
Joined: Wed Jun 16, 2010 8:21 am
Thanked: 13 times
Followed by:1 members

by rohit_gmat » Sun Sep 11, 2011 9:02 am
cans wrote:n people came. fees = f.. fee received = fn
A) (f- f/7500)(n+100) = fn
insufficient.
B) (f+1.5)(n-100)=fn -> 1.5n -100f -150=0.
3n - 200f - 300 =0 insufficient.
combining A,B we have 2 eqn and 2 variable. Thus IMO C
hi cans.. need ur help... for stmnt 1, i did the following :

(f - 0.0075f) (n + 100) = fn
f (1 - 0.0075) (n + 100) = fn
and i cancel f out on both sides...
(1 - 0.0075) (n+100) = n
n + 100 - 0.0075n - 0.75 = n
100 = 0.0075n + 0.75
and thats solvable to n...

what did i do wrong in here?

User avatar
Legendary Member
Posts: 1309
Joined: Mon Apr 04, 2011 5:34 am
Location: India
Thanked: 310 times
Followed by:123 members
GMAT Score:750

by cans » Sun Sep 11, 2011 9:16 am
I made a mistake in A.... it is as you mentioned but when you solve for n, its not an integer. But # of people should be integer. so A can't be correct....... I think question is wrong......
If my post helped you- let me know by pushing the thanks button ;)

Contact me about long distance tutoring!
[email protected]

Cans!!

User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pm
Location: New York, NY
Thanked: 13060 times
Followed by:1906 members
GMAT Score:790

by GMATGuruNY » Sun Sep 11, 2011 11:49 am
rohit_gmat wrote:Q. If everyone was charged the same fee, how many people came?
A. If the fee had been 0.75 less and 100 more people came, the club would have received the same amount.
B. If fee had been $1.50 more and 100 fewer people came, the club would have received the same amount.

source : 198 700+ Qs list

OA : C
IMO : A

plz provide explanations as well.. thanks !! :)
I've corrected a typo in the posted question: Statement 1 should say if the fee had been .75 less.

Let the number of people = p.
Let the fee = f.
Sum of the fees = pf.

Statement 1: If the fee had been 0.75 less and 100 more people came, the club would have received the same amount.
The sum here = (p+100)(f-75).
Since the sum here is the same as the original sum:
(p+100)(f-75) = pf.
pf - 75p + 100f - 7500 = pf.
-75p + 100f = 7500.
No way to solve for p.
Insufficient.

Statement 2: If fee had been $1.50 more and 100 fewer people came, the club would have received the same amount.
The sum of the fees here = (p-100)(f+150)
Since the sum here is the same as the original sum:
(p-100)(f+150) = pf.
pf + 150p - 100f - 15000 = pf.
150p - 100f = 15,000.
No way to solve for p.
Insufficient.

Statements 1 and 2 combined:
Two variables, two distinct linear equations.
Thus, we can solve for p.
Sufficient.

The correct answer is C.
Last edited by GMATGuruNY on Thu May 10, 2012 5:00 am, edited 1 time in total.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3

Legendary Member
Posts: 608
Joined: Sun Jun 19, 2011 11:16 am
Thanked: 37 times
Followed by:8 members

by saketk » Mon Sep 12, 2011 8:51 am
I think if we solve the original question (with typo error) then the answer should be A.

Newbie | Next Rank: 10 Posts
Posts: 1
Joined: Wed Jul 02, 2014 11:32 am

by just_dan » Thu Aug 14, 2014 2:43 am
rohit_gmat wrote:
cans wrote:n people came. fees = f.. fee received = fn
A) (f- f/7500)(n+100) = fn
insufficient.
B) (f+1.5)(n-100)=fn -> 1.5n -100f -150=0.
3n - 200f - 300 =0 insufficient.
combining A,B we have 2 eqn and 2 variable. Thus IMO C
hi cans.. need ur help... for stmnt 1, i did the following :

(f - 0.0075f) (n + 100) = fn
f (1 - 0.0075) (n + 100) = fn
and i cancel f out on both sides...
(1 - 0.0075) (n+100) = n
n + 100 - 0.0075n - 0.75 = n
100 = 0.0075n + 0.75
and thats solvable to n...

what did i do wrong in here?
Yeah, your solution seems correct, thus A shall be the right answer!

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pm
Location: Vancouver, BC
Thanked: 5254 times
Followed by:1268 members
GMAT Score:770

by Brent@GMATPrepNow » Thu Aug 14, 2014 7:50 am
Each person attending a fund-raising party for a certain club was charged the same admission fee. How many people attended the party?

1) If the admission fee had been $0.75 less and 100 more people had attended, the club would have received the same amount in admission fees.

2) If the admission fee had been $1.50 more and 100 fewer people had attended, the club would have received the same amount in admission fees.
Let F = admission fee
Let N = number of attendees
So, the TOTAL revenue = FN

Target question: What is the value of N?

Statement 1: If the admission fee had been $0.75 less and 100 more people had attended, the club would have received the same amount in admission fees.
In other words, if the fee had been (F - 0.75) and the number of attendees had been (N + 100) the total revenue would still be FN
We can write: (F - 0.75)(N + 100) = FN
Expand: FN + 100F - 0.75N - 75 = FN
Simplify: 100F - 0.75N - 75 = 0
Since we cannot solve this equation for N, we cannot answer the target question with certainty.
So statement 1 is NOT SUFFICIENT

Statement 2: If the admission fee had been $1.50 more and 100 fewer people had attended, the club would have received the same amount in admission fees.
In other words, if the fee had been (F + 1.50) and the number of attendees had been (N - 100) the total revenue would still be FN
We can write: (F + 1.50)(N - 100) = FN
Expand: FN - 100F + 1.5N - 150 = FN
Simplify: -100F + 1.5N - 150 = 0
Since we cannot solve this equation for N, we cannot answer the target question with certainty.
So statement 2 is NOT SUFFICIENT

Statements 1 and 2 combined
Statement 1 tells us that 100F - 0.75N - 75 = 0
Statement 2 tells us that -100F + 1.5N - 150 = 0
Here we have two different linear equations involving two variables.
Since we COULD solve this system for N, we could answer the target question with certainty.
So, the combined statements are SUFFICIENT

ASIDE: We don't need to actually solve the system. We need only recognize that we have SUFFICIENT information to do so.

Answer = C

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image