If BE CD, and BC = AB = 3, AE = 4 and CD = 10, what is the area of trapezoid BEDC?
12
18
24
30
48
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trapezoid in triangle
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AleksandrM
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I think that the answer is B, 18.
The bigger triangle ACD is a special 6-8-10 triangle. So the area of the bigger triangle is 6 x 8/2 = 24 [note also that since the side AD is 8, then ED = 4]
Then, claculate the area of the smaller special triangle 3-4-5 ABE, which is 3 x 4/2 = 6
Then subtract the area of smaller triangle from the area of the bigger triangle and you get 24 - 6 = 18.
Hope I am right!
The bigger triangle ACD is a special 6-8-10 triangle. So the area of the bigger triangle is 6 x 8/2 = 24 [note also that since the side AD is 8, then ED = 4]
Then, claculate the area of the smaller special triangle 3-4-5 ABE, which is 3 x 4/2 = 6
Then subtract the area of smaller triangle from the area of the bigger triangle and you get 24 - 6 = 18.
Hope I am right!
