Is the positive integer z a prime number?
1) z and the square root of integer y have the same number of unique prime factors.
2) z and the perfect square y have the same number of unique factors.
Statement (1) BY ITSELF is sufficient to answer the question, but statement (2) by itself is not.
Statement (2) BY ITSELF is sufficient to answer the question, but statement (1) by itself is not.
Statements (1) and (2) TAKEN TOGETHER are sufficient to answer the question, even though NEITHER statement BY ITSELF is sufficient.
EITHER statement BY ITSELF is sufficient to answer the question.
Statements (1) and (2) TAKEN TOGETHER are NOT sufficient to answer the question, requiring more data pertaining to the problem.
Kaplan quiz 6, question 6, https://www.scribd.com/doc/58999877/GMAT ... et-6-Quant
Is the positive integer z a prime number
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- saxenashobhit
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Hi,
From(1):
if y = 3^2, sqrt(y) = 3 and z can be either 3 or 3^3(Both have only 3 as prime factor)
So, z can be prime or not
Not sufficient
From(2):
if y is a perfect square. It has at odd number of factors. So, z has odd number of factors.
So, z is definitely not prime because a prime has only 2 factors(1 and itself)
Sufficient
Hence, B
From(1):
if y = 3^2, sqrt(y) = 3 and z can be either 3 or 3^3(Both have only 3 as prime factor)
So, z can be prime or not
Not sufficient
From(2):
if y is a perfect square. It has at odd number of factors. So, z has odd number of factors.
So, z is definitely not prime because a prime has only 2 factors(1 and itself)
Sufficient
Hence, B
Last edited by Frankenstein on Thu Jul 07, 2011 5:56 am, edited 1 time in total.
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Things are not what they appear to be... nor are they otherwise
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Statement 1 is not sufficient; if y is 9, then z could be 3 or 9, so z could be prime or not.saxenashobhit wrote:Is the positive integer z a prime number?
1) z and the square root of integer y have the same number of unique prime factors.
2) z and the perfect square y have the same number of unique factors.
Does Statement 2 say 'unique factors', or 'unique prime factors'? If the question only says 'unique factors' in Statement 2, then Statement 2 is sufficient alone. Perfect squares must have an odd number of factors in total, whereas prime numbers always have 2 factors in total, so if Statement 2 is true, then z cannot be prime, and Statement 2 is sufficient to give a 'no' answer to the question.
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Careful here - that's true for every positive perfect square with one exception: 1 has only 1 positive factor.Frankenstein wrote:
if y is a perfect square. It has at least 3 factors.
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- saxenashobhit
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Hi Ian,
Option B in Kaplan test says 'unique factors'. I had marked B by thinking on same lines as you but Kaplan said B its wrong. I don't have OA but I feel this one question's answer may be wrong in Kaplan's system
Option B in Kaplan test says 'unique factors'. I had marked B by thinking on same lines as you but Kaplan said B its wrong. I don't have OA but I feel this one question's answer may be wrong in Kaplan's system
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Thanks Ian. As soon as I posted, I actually thought of changing and adding that z is a perfect square. But, I have been having problem with my internet. So, I couldn't edit earlier.Ian Stewart wrote:Careful here - that's true for every positive perfect square with one exception: 1 has only 1 positive factor.Frankenstein wrote:
if y is a perfect square. It has at least 3 factors.
Cheers!
Things are not what they appear to be... nor are they otherwise
Things are not what they appear to be... nor are they otherwise