If \frac{x}{|x|}<x which of the following must be true about x?
(A) x>1
(B) x>-1
(C) |x|<1
(D) |x|=1
(E) |x|^2>1
a is my answer choice. whats yours>?
a ps from gmat club
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The notation in the question "\frac{x}{|x|}<x" is used in a mathematical typesetting environment called TeX - it's not something you'll ever see on the GMAT. The question should begin:diebeatsthegmat wrote:If \frac{x}{|x|}<x which of the following must be true about x?
(A) x>1
(B) x>-1
(C) |x|<1
(D) |x|=1
(E) |x|^2>1
a is my answer choice. whats yours>?
If x/|x| < x, which of the following...
Now x/|x| is either equal to 1 (if x is positive) or to -1 (if x is negative). So we can rephrase the inequality:
* if x > 0, then 1 < x
* if x < 0, then -1 < x
So there are two ranges of possible values for x; either x > 1, or -1 < x < 0.
From here you can see that the only answer which *must* be true is B, since if x is in either of the ranges above, x is certainly greater than -1. Most of the other answers (besides D) *could* be true, but are not always true.
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- sourabh33
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Hi Ian
I have a small doubt regarding statements A & B.
I can't think of any value of x>1 that will not be true for the equation x/|x| < X
Versus For option B (x>-1), when x = 0, then the equation x/|x| < X may not be true
Please help.
I have a small doubt regarding statements A & B.
I can't think of any value of x>1 that will not be true for the equation x/|x| < X
Versus For option B (x>-1), when x = 0, then the equation x/|x| < X may not be true
Please help.
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- Ian Stewart
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I think you must be looking at the question backwards. We *know* that x/|x| is less than x. We want to know which answer choice *must* be true. It doesn't need to be true that x > 1, because x could be equal to -0.5, so A cannot be the right answer.sourabh33 wrote:Hi Ian
I have a small doubt regarding statements A & B.
I can't think of any value of x>1 that will not be true for the equation x/|x| < X
Versus For option B (x>-1), when x = 0, then the equation x/|x| < X may not be true
Please help.
I think you're trying to answer the opposite question. That is, you're assuming that answer A is true, and you're trying to prove that x/|x| is less than x. It certainly is if x > 1, but that doesn't make A correct here, because that's not what the question is asking you to do.
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- sourabh33
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Thank you so much for the clarification.
Now in statement x>-1
In Range -1<x<0 the given equation is true
In Range x=0 the given equation is not defined
In Range 0<x<1 the given equation x/|x| is not true (it is actually greater than x (0.5/0.5 > 0.5))
In Range x=1 the equation is not true
In Range 1<x the equation is true
But, as you said in your post that two ranges possible for x are x>1 and -1<x<0, than x cannot be 0 because either x has to be greater than 1 or x has to be in between -1 and 0.Ian Stewart wrote: * if x > 0, then 1 < x
* if x < 0, then -1 < x
So there are two ranges of possible values for x; either x > 1, or -1 < x < 0.
Now in statement x>-1
In Range -1<x<0 the given equation is true
In Range x=0 the given equation is not defined
In Range 0<x<1 the given equation x/|x| is not true (it is actually greater than x (0.5/0.5 > 0.5))
In Range x=1 the equation is not true
In Range 1<x the equation is true