Running at their respective constant rates, machine X takes 2 days longer to produce w widgets than machine Y. At these rates, if the two machines together produce (5/4)w widgets in 3 days, how many days would it take machine X alone to produce 2w widgets?
A. 4
B. 6
C. 8
D. 10
E. 12
how many days would it take machine X alone to produce 2w
This topic has expert replies
ANS 12..
Suppose machine Y produces w widgets in d days
so, X produces same in d+2 days
In 1 day Y produces w/d and X produces w/(d+2) widgets
Working together they will produce w/d + w/(d+2) = [2w(d+1)]/[d(d+2)] widgets in 1 day
in 3 days they produce 3*[2w(d+1)]/[d(d+2)] = 5w/4
Solve to get d =4
x produces w widgets in 4+2 = 6 days
so, 2w widgets will be produces in 12 days
OA???
Suppose machine Y produces w widgets in d days
so, X produces same in d+2 days
In 1 day Y produces w/d and X produces w/(d+2) widgets
Working together they will produce w/d + w/(d+2) = [2w(d+1)]/[d(d+2)] widgets in 1 day
in 3 days they produce 3*[2w(d+1)]/[d(d+2)] = 5w/4
Solve to get d =4
x produces w widgets in 4+2 = 6 days
so, 2w widgets will be produces in 12 days
OA???
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i realize this is an old post but could someone show me the actual calculation that goes from this step -
in 3 days they produce 3*[2w(d+1)]/[d(d+2)] = 5w/4
to this step -
Solve to get d =4
i seem to be making a simple error somewhere...
in 3 days they produce 3*[2w(d+1)]/[d(d+2)] = 5w/4
to this step -
Solve to get d =4
i seem to be making a simple error somewhere...
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Let the no. of days that Y takes is d
then no. of days that X takes will be d+2
X's rate = w/(d+2)
Y's rate = w/d
[w/d + w/(d+2)] * 3 = 5w/4
(w(d+2) + wd) /d(d+2) = 5w/12
wd + 2w + wd = 5wd(d+2)/12
24w(d+1) = 5wd(d+2)
24(d+1) = 5d(d+2)
24d + 24 = 5d^2 + 10d
5d^2 -14d - 24 = 0
5d^2 - 20d + 6d -24 = 0
(5d+6) ( d-4) = 0
d=-6/5 or 4
time cannot be negative, hence d=4
X produces w in d+2 = 4+2
2w will be produced in 6+6 = 12 days
Hope this helps.
then no. of days that X takes will be d+2
X's rate = w/(d+2)
Y's rate = w/d
[w/d + w/(d+2)] * 3 = 5w/4
(w(d+2) + wd) /d(d+2) = 5w/12
wd + 2w + wd = 5wd(d+2)/12
24w(d+1) = 5wd(d+2)
24(d+1) = 5d(d+2)
24d + 24 = 5d^2 + 10d
5d^2 -14d - 24 = 0
5d^2 - 20d + 6d -24 = 0
(5d+6) ( d-4) = 0
d=-6/5 or 4
time cannot be negative, hence d=4
X produces w in d+2 = 4+2
2w will be produced in 6+6 = 12 days
Hope this helps.
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This question is from GMATPrep. An efficient way to solve this problem is to plug in the answer choices.netigen wrote:Running at their respective constant rates, machine X takes 2 days longer to produce w widgets than machine Y. At these rates, if the two machines together produce (5/4)w widgets in 3 days, how many days would it take machine X alone to produce 2w widgets?
A. 4
B. 6
C. 8
D. 10
E. 12
Let w=12.
In 3 days, X and Y need to produce 5/4*w = 5/4*12 = 15 widgets.
The answer choices represent the time for X to produce 2w=24 widgets.
Answer choice C: 8 days for X to produce 24 widgets
Thus, X produces 12 widgets in 4 days.
Since X takes 2 days longer, Y produces 12 widgets in 4-2=2 days.
Rate for X = w/t = 12/4 = 3/day.
Rate for Y = w/t = 12/2 = 6/day.
Combined rate for X+Y = 3+6 = 9/day .
Work completed in 3 days = r*t = 9*3 = 27 widgets.
Incorrect: almost DOUBLE the required number of widgets (15) is being produced.
Thus, X and Y need to work MUCH MORE SLOWLY, implying that the time for X to produce 24 widgets must be MUCH LONGER.
Answer choice E: 12 days for X to produce 24 widgets
Thus, X produces 12 widgets in 6 days.
Since X takes 2 days longer, Y produces 12 widgets in 6-2=4 days.
Rate for X = w/t = 12/6 = 2/day.
Rate for Y = w/t = 12/4 = 3/day.
Combined rate for X+Y = 2+3 = 5/day.
Work completed in 3 days = r*t = 5*3 = 15 widgets. Success!
The correct answer is E.
Last edited by GMATGuruNY on Mon Nov 07, 2011 10:02 am, edited 1 time in total.
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NICEGMATGuruNY wrote:This question is from GMATPrep. An efficient way to solve this problem is to plug in the answer choices.netigen wrote:Running at their respective constant rates, machine X takes 2 days longer to produce w widgets than machine Y. At these rates, if the two machines together produce (5/4)w widgets in 3 days, how many days would it take machine X alone to produce 2w widgets?
A. 4
B. 6
C. 8
D. 10
E. 12
Let w=12.
In 3 days, X and Y need to produce 5/4*w = 5/4*12 = 15 widgets.
The answer choices represent the time for X to produce 2w=24 widgets.
Answer choice C: 8 days for X to produce 24 widgets
Thus, X produces 12 widgets in 4 days.
Since X takes 2 days longer, Y produces 12 widgets in 4-2=2 days.
Rate for X = w/t = 12/4 = 3/day.
Rate for Y = w/t = 12/2 = 6/day.
Combined rate for X+Y = 3+6 = 9/day .
Work completed in 3 days = r*t = 9*3 = 27 widgets.
Incorrect. We need much less work to get done, so the time for X must be much longer.
Answer choice E: 12 days for X to produce 24 widgets
Thus, X produces 12 widgets in 6 days.
Since X takes 2 days longer, Y produces 12 widgets in 6-2=4 days.
Rate for X = w/t = 12/6 = 2/day.
Rate for Y = w/t = 12/4 = 3/day.
Combined rate for X+Y = 2+3 = 5/day.
Work completed in 3 days = r*t = 5*3 = 15 widgets. Success!
The correct answer is E.
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