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- anshumishra
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1 -> R
2,4,6,8 -> C, M
5 -> M
3, 7 -> V,P, D
So, total no. of arrangements = 1*2*3*2*1*2*3*2 = 144
2,4,6,8 -> C, M
5 -> M
3, 7 -> V,P, D
So, total no. of arrangements = 1*2*3*2*1*2*3*2 = 144
Thanks
Anshu
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Anshu
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- Rahul@gurome
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1st place - Monet - 1 way
2nd, 4th, 6th, 8th place - Cezzane or Monet - 2^4 -16 ways
5th place - Manet - 1 way.
2 - 3rd and 7th places are now remaining.
They can have Van Gogh, Pissaro or Degas in 3^2 = 9 ways.
So required number of ways of arranging the paintings is 1*16*1*9= 144 ways.
2nd, 4th, 6th, 8th place - Cezzane or Monet - 2^4 -16 ways
5th place - Manet - 1 way.
2 - 3rd and 7th places are now remaining.
They can have Van Gogh, Pissaro or Degas in 3^2 = 9 ways.
So required number of ways of arranging the paintings is 1*16*1*9= 144 ways.
Rahul Lakhani
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- Rahul@gurome
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Yes. What you need to do is to find out that for each place, how many ways of putting a painting is possible.N:Dure wrote:Thanks Anush & Rahul
@ Rahul the way you do it for C & M is more of counting right? Is this the only way to do it or u can do it in a comb way?
Then multiply them all together to get the required answer.
Rahul Lakhani
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