if f is the function defined for all k by f(k)=k^5/16, what is f(2k) in terms of f(k)?
a. 1/8 f(k)
b. 5/8 f(k)
c. 2 f(k)
d. 10 f(k)
e. 32 f(k)
function
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i was lostgmatguy16 wrote:imo e f(2k)= (2k) ^ 5 / 16 = 32 k ^5/16 = 32 f(k)
i tried this:
(2k)^(5/16)
then
{(2^5)(k^5)}^(1/16)
next:
[32k^5]^(1/16)
so i did it until here.... was i doing something wrong?
LEARNING ENGLIS H
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andes1,
U r getting wrong man! The Qs is saying - f(2k)= (2k) ^ 5 / 16 means f(2k)= ((2k) ^ 5) / 16, I think now u can get the idea where u misunderstood the Qs!
U r getting wrong man! The Qs is saying - f(2k)= (2k) ^ 5 / 16 means f(2k)= ((2k) ^ 5) / 16, I think now u can get the idea where u misunderstood the Qs!
Correct me If I am wrong
Regards,
Amitava
Regards,
Amitava
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haha thanks a lot... was a silly error from my part.camitava wrote:andes1,
U r getting wrong man! The Qs is saying - f(2k)= (2k) ^ 5 / 16 means f(2k)= ((2k) ^ 5) / 16, I think now u can get the idea where u misunderstood the Qs!
LEARNING ENGLIS H