Q: In the rectangular coordinate system, points (4, 0) and (– 4, 0) both lie on circle C. What is the
maximum possible value of the radius of C ?
A. 2
B. 4
C. 8
D. 16
E. There is no finite maximum value.
How to arrive at 16?
Circle & rectangular coordinate system
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Last edited by crackgmat007 on Fri May 29, 2009 7:24 am, edited 1 time in total.
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Well, if you do arrive at 16, you're not getting the correct answer. The radius here can be as large as you want. For example, take the point (0,100) as the center of the circle. The two points (4,0) and (-4,0) are the same distance from (0,100), so we can certainly draw a circle with center (0,100) that passes through those two points. The radius of that circle is going to be a bit more than 100 (you can find it exactly by solving for r in r^2 = 100^2 + 4^2, though we don't need to do that here). So the answer is E.crackgmat007 wrote:Q: In the rectangular coordinate system, points (4, 0) and (– 4, 0) both lie on circle C. What is the
maximum possible value of the radius of C ?
A. 2
B. 4
C. 8
D. 16
E. There is no finite maximum value.
How to arrive at 16?
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I am not able to understand the explanation. If the centree of circle is 0,100, how can draw a circle which passes thru' 4,0 and -4,0.
I think the maximum radius is 4, (the line connecting 4,0 and -4,0 is the diameter)
Please correct me if I am wrong
I think the maximum radius is 4, (the line connecting 4,0 and -4,0 is the diameter)
Please correct me if I am wrong
any point eqi-distant from both the points can be the center or the circle so there are infinite points that satisfy the equation
the y axis being one set of points. (0,x) where x= real numbers
so E is the answer
the y axis being one set of points. (0,x) where x= real numbers
so E is the answer