any easy of solving this kind of problem

This topic has expert replies
Senior | Next Rank: 100 Posts
Posts: 47
Joined: Mon Dec 04, 2006 1:43 am
Thanked: 1 times

any easy of solving this kind of problem

by sochatte » Wed Nov 28, 2007 10:49 pm
Q13:
If n is a positive integer, what is the remainder when 3exp(8n+3) + 2 is divided by 5?

A. 0
B. 1
C. 2
D. 3
E. 4

Master | Next Rank: 500 Posts
Posts: 195
Joined: Sun Oct 21, 2007 4:33 am
Thanked: 10 times

by sankruth » Thu Nov 29, 2007 4:15 am
n = 1, 8n+3=11 so units digit of 3^(11) = 7 and 3^(11) + 2 ends with 9

n = 2, 8n+3=19 so units digit of 3^(19) = 7 and 3^(19) + 2 ends with 9

so answer is E (correct??)

Senior | Next Rank: 100 Posts
Posts: 47
Joined: Mon Dec 04, 2006 1:43 am
Thanked: 1 times

by sochatte » Thu Nov 29, 2007 10:25 am
yes E is right.....

Junior | Next Rank: 30 Posts
Posts: 22
Joined: Wed Nov 28, 2007 10:51 am
Thanked: 3 times

by sirikesav » Fri Nov 30, 2007 2:49 am
In this problem just increase the power as much as you can
for example we can write the above example as

(3.3^(2(4n+1)) + 2)/5
=>( 3.9^(4n+1) + 2)/5

for first part as 9%5 = 4 and 4 ^4n+1is always a number with units digit as 4 hence remainder is 4 as 4n+1 is Odd

3* 4 = 12 & 12%5 = 2

Hence adding Both 2+2 = 4

Hence the remainder is 4