I always seem to have problems with conversions, can someone explain this question?
Thanks!
Correct answer is C
This looked pretty straightforward....till I got it wrong. Help me with my error.
Thanks!
random gmat prep questions
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As for the 2nd problem...
ABCD all have possible choices that make the solution a straight line.
eg. x^4 >=1 x=2,3,....or -2,-3....
Choice E states that the line 3x+4 is constrained at two ends
3x+4 >=2 so x>=-2/3
3x+4 <=6 so x<=2/3
so the line 3x+4 is constrained at -2/3<=X<=2/3
so E is the answer
ABCD all have possible choices that make the solution a straight line.
eg. x^4 >=1 x=2,3,....or -2,-3....
Choice E states that the line 3x+4 is constrained at two ends
3x+4 >=2 so x>=-2/3
3x+4 <=6 so x<=2/3
so the line 3x+4 is constrained at -2/3<=X<=2/3
so E is the answer
Last edited by jrbrown2 on Wed Nov 21, 2007 8:32 am, edited 1 time in total.
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Thanks jrbrown2.
For the second question, it said finite line, so I eliminated options A, B & C, but couldn't decide between D or E.
How is D not finite? It looks like its constricted by 2 & 5.
Thanks
For the second question, it said finite line, so I eliminated options A, B & C, but couldn't decide between D or E.
How is D not finite? It looks like its constricted by 2 & 5.
Thanks
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For question 1,
Did you mean m & s cancels out after you isolate Y?
Also, I always get confused when I have to setup equations like this.....when the question says 'what is A in terms of B', how do I set that up as an equation?
For questions like "what is a% of b", I typically write 'x=a/100* b', but with 'in terms of' questions, I don't quite know how to write that.
Can you help?
Thanks!
Did you mean m & s cancels out after you isolate Y?
Also, I always get confused when I have to setup equations like this.....when the question says 'what is A in terms of B', how do I set that up as an equation?
For questions like "what is a% of b", I typically write 'x=a/100* b', but with 'in terms of' questions, I don't quite know how to write that.
Can you help?
Thanks!
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- Master | Next Rank: 500 Posts
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D says that x is between 2 and 5 inclusive, so x can be 2,3,4, or 5
To rewrite:
x=2
x=3
x=4
x=5
they are all straight lines without constraints
In this case x m/s and y km/hr. Equate the two equations, making sure to keep the units constant (i.e. km=1000m, 1 hr = 3600s).
x m/s = y km/hr
x m/s = y (1000m)/(3600s)
Isolating y,
y = x m*3600s/(1000m*s) <----the m and s cancel out here
and simplify
y=18x/5
To rewrite:
x=2
x=3
x=4
x=5
they are all straight lines without constraints
When a question asks this there are usually two equations (with different variables) that are equal to each other.when the question says 'what is A in terms of B', how do I set that up as an equation?
In this case x m/s and y km/hr. Equate the two equations, making sure to keep the units constant (i.e. km=1000m, 1 hr = 3600s).
x m/s = y km/hr
x m/s = y (1000m)/(3600s)
Isolating y,
y = x m*3600s/(1000m*s) <----the m and s cancel out here
and simplify
y=18x/5
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Yes, its on the number line and that was where I got stuck as well. If I followed through with the calculations, I would've realized E was the answer.
For E- if you subtract -4 from all 3 parts of the equation like so:
2<=3x+4<=6
-4 -4 -4
You get: -2<=3x<=2
which when broken into 2 parts:
-2<3x>= -2/3
And 3x<=2 which gives you x<2>=-2/3 and x<= 2/3.
Hope that helps.
For E- if you subtract -4 from all 3 parts of the equation like so:
2<=3x+4<=6
-4 -4 -4
You get: -2<=3x<=2
which when broken into 2 parts:
-2<3x>= -2/3
And 3x<=2 which gives you x<2>=-2/3 and x<= 2/3.
Hope that helps.