At a certain school, the ratio of the number of second
graders to the number of fourth graders is 8 to 5, and
the ratio of the number of first graders to the number of
second graders is 3 to 4. If the ratio of the number of
third graders to the number of fourth graders is 3 to 2 ,
what is the ratio of the number of first graders to the
number of third graders?
a. 16 to 15
b. 9 to 5
c. 5 to 16
d. 5 to 4
e. 4 to 5
Hi, I want to know how i can do this question faster?
I can solve it but i take almost 2 minutes!!
any shortcuts for these types of questions?
2nd /4th = 8/5
1st /2nd = 3/4
3rd/4th =3/2
find 1st/3rd =?
3rd/4th = 3/2 * 5/5 = 15/10
2nd /4th = 8/5 * 2/2 = 16/10
1st /2nd = 3/4 *4/4 = 12/16
so 1st/3rd = 12/15 = 4/5
but how can i do this faster? including reading time im touching almost 2.5 minutes!
At a certain school, the ratio of the number of second grad
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After 1st sentence, in one's mind,
1st:2nd:4th = 6:8:5
3rd:4th = 3:2
To match 1st and 2nd equations, multiply 1st eq by 2 and 2nd eq by 5
1st:2nd:3rd:4th = 12:16:15:10
From this, 1st:3rd = 12:15 = 4:5
Hope this helps. Thanks.
1st:2nd:4th = 6:8:5
3rd:4th = 3:2
To match 1st and 2nd equations, multiply 1st eq by 2 and 2nd eq by 5
1st:2nd:3rd:4th = 12:16:15:10
From this, 1st:3rd = 12:15 = 4:5
Hope this helps. Thanks.
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Thanks! this is faster than what i was doing!4GMAT_Mumbai wrote:After 1st sentence, in one's mind,
1st:2nd:4th = 6:8:5 *******the 6 is a mistake right? should be 3:8:5 no?
3rd:4th = 3:2
To match 1st and 2nd equations, multiply 1st eq by 2 and 2nd eq by 5
1st:2nd:3rd:4th = 12:16:15:10
From this, 1st:3rd = 12:15 = 4:5
Hope this helps. Thanks.
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Hi,
This is my apporach..
2nd /4th = 8/5
1st /2nd = 3/4
3rd/4th =3/2
2nd/4th * 1st/2nd * 4th/3rd = 1st/3rd= 8/5*3/4*2/3= 4/5
This is my apporach..
2nd /4th = 8/5
1st /2nd = 3/4
3rd/4th =3/2
2nd/4th * 1st/2nd * 4th/3rd = 1st/3rd= 8/5*3/4*2/3= 4/5
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Hi, this works!!! but im not sure if there's an actual mathematical concept here or that the answer is just a coincidence i.e. that all given ratio's product is the answer. can you explain why & how you knew that multiplying all the given ratios would give the ratio that is being asked?muralithe1 wrote:Hi,
This is my apporach..
2nd /4th = 8/5
1st /2nd = 3/4
3rd/4th =3/2
2nd/4th * 1st/2nd * 4th/3rd = 1st/3rd= 8/5*3/4*2/3= 4/5
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- eloka
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Okay...this is my approach..eloka's way
x = 2nd grade
y= 4th grade
m= 1st grade
k= 3rd grade
x:y = 8:5 (*2) ===> x:y = 16:10======> x:y = 16:10
m:x=3:4 (*2)====> m : x = 6: 8 (*2) ==> m = 12: 16
k:y = 3:2(*5)====> k:y = 15:10======> k:y = 15:10
Now we know x and y are equal to all the ration. Therefore, we can find the ratio solution for m:k = 12: 15 = 4:5
m/k = 4/5
x = 2nd grade
y= 4th grade
m= 1st grade
k= 3rd grade
x:y = 8:5 (*2) ===> x:y = 16:10======> x:y = 16:10
m:x=3:4 (*2)====> m : x = 6: 8 (*2) ==> m = 12: 16
k:y = 3:2(*5)====> k:y = 15:10======> k:y = 15:10
Now we know x and y are equal to all the ration. Therefore, we can find the ratio solution for m:k = 12: 15 = 4:5
m/k = 4/5
Warm wishes to all of you who are striving to conquer the GMAT
Eloka
Indonesia
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Eloka
Indonesia
https://lavachoco.blocked
All I need is 450 GMAT score!! thats all, Geez
- eloka
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Okay...this is my approach..eloka's way
x = 2nd grade
y= 4th grade
m= 1st grade
k= 3rd grade
x:y = 8:5 multiply with (*2) ===> x:y = 16:10======> x:y = 16:10
m=3: 4 multiply with (*2)====> m : x = 6: 8 multiply again with (*2) ==> m = 12: 16
k:y = 3: 2 multiply with (*5)====> k:y = 15:10======> k:y = 15:10
keep multiplying until you find x and y in a ratio group shares the same number. As you can see
x/y = 16/10
m/x = 12/16
k/y=15/10
x is 16 and y is 10....so now we can find ratio of m to k
Now we know x and y are equal to all the ration. Therefore, we can find the ratio solution for m:k = 12: 15 = 4:5
m/k = 4/5
x = 2nd grade
y= 4th grade
m= 1st grade
k= 3rd grade
x:y = 8:5 multiply with (*2) ===> x:y = 16:10======> x:y = 16:10
m=3: 4 multiply with (*2)====> m : x = 6: 8 multiply again with (*2) ==> m = 12: 16
k:y = 3: 2 multiply with (*5)====> k:y = 15:10======> k:y = 15:10
keep multiplying until you find x and y in a ratio group shares the same number. As you can see
x/y = 16/10
m/x = 12/16
k/y=15/10
x is 16 and y is 10....so now we can find ratio of m to k
Now we know x and y are equal to all the ration. Therefore, we can find the ratio solution for m:k = 12: 15 = 4:5
m/k = 4/5
Warm wishes to all of you who are striving to conquer the GMAT
Eloka
Indonesia
https://lavachoco.blocked
All I need is 450 GMAT score!! thats all, Geez
Eloka
Indonesia
https://lavachoco.blocked
All I need is 450 GMAT score!! thats all, Geez