What is the ratio of the average (arithmetic mean) height of students in class X to the average height of students in class Y?
(1) The average height of the students in class X is 120 centimeters.
(2) The average height of the students in class X and class Y combined is 126 centimeters.
OA:E
I know that this problem has been beaten to death, but I have a question. Why can't you use a harmonic mean to solve it?
I got C by using a harmonic mean. Since, technically an average height could be considered a rate, right? (Total height / number of students).
Harmonic mean = (2*(120)*Y)/(120 + Y) = 126. --> Then you simply solve for Y.
Can somebody explain to me, why the harmonic mean is not applicable in this scenario.
Harmonic Mean Solution?
This topic has expert replies
- Stuart@KaplanGMAT
- GMAT Instructor
- Posts: 3225
- Joined: Tue Jan 08, 2008 2:40 pm
- Location: Toronto
- Thanked: 1710 times
- Followed by:614 members
- GMAT Score:800
Timer
00:00
Your Answer
A
B
C
D
E
Global Stats
Hi,student22 wrote:What is the ratio of the average (arithmetic mean) height of students in class X to the average height of students in class Y?
(1) The average height of the students in class X is 120 centimeters.
(2) The average height of the students in class X and class Y combined is 126 centimeters.
OA:E
I know that this problem has been beaten to death, but I have a question. Why can't you use a harmonic mean to solve it?
I got C by using a harmonic mean. Since, technically an average height could be considered a rate, right? (Total height / number of students).
Harmonic mean = (2*(120)*Y)/(120 + Y) = 126. --> Then you simply solve for Y.
Can somebody explain to me, why the harmonic mean is not applicable in this scenario.
to use a weighted average formula in this kind of question, you need to know the average of each group and the weight of each group. Since we don't know the weight of each group, there's no way to solve using harmonic mean.
Picking numbers (that are in accord with all the information given):
1 student in x with height 120, 1 student in y with height 132. Ratio of x:y is 120:132.
1 student in x with height 120, 2 students in y with height 129. Ratio of x:y is 120:129.
We can get different ratios, so we don't have enough information to solve the problem.
Stuart Kovinsky | Kaplan GMAT Faculty | Toronto
Kaplan Exclusive: The Official Test Day Experience | Ready to Take a Free Practice Test? | Kaplan/Beat the GMAT Member Discount
BTG100 for $100 off a full course
GMAT/MBA Expert
- [email protected]
- Elite Legendary Member
- Posts: 10392
- Joined: Sun Jun 23, 2013 6:38 pm
- Location: Palo Alto, CA
- Thanked: 2867 times
- Followed by:511 members
- GMAT Score:800
Timer
00:00
Your Answer
A
B
C
D
E
Global Stats
Hi All,
We're asked for the RATIO of the average (arithmetic mean) height of students in Class X to the average height of students in Class Y. This is a great example of a 'concept question', meaning that you don't have to do much math to answer it if you recognize the concept(s) involved.
1) The average height of the students in Class X is 120 centimeters.
Fact 1 gives us the average height for Class X, but tells us nothing about the average height of Class Y.
Fact 1 is INSUFFICIENT
2) The average height of the students in Class X AND Class Y combined is 126 centimeters.
Fact 2 tells us the average height of ALL students, but we have know way to determine the average heights in just Class X or just Class Y.
Fact 2 is INSUFFICIENT
Combined, we know
-The average height of the students in Class X is 120 centimeters.
-The average height of the students in Class X AND Class Y combined is 126 centimeters.
We don't know the NUMBER of students in each class, so the information in Fact 2 will 'skew' based on the number of students in Class X vs. the number in Class Y. For example, if we have an EQUAL number of students in both classes, then the average height for Class Y would be (120+Y)/2 = 126 --> Y = 132 centimeters. However, if the number of students is NOT equal, then the average height of Class Y will change (it could be higher or lower depending on whether Class X had more or less students). Thus, there's no way to determine the exact ratio of the average heights.
Combined, INSUFFICIENT
Final Answer: E
GMAT assassins aren't born, they're made,
Rich
We're asked for the RATIO of the average (arithmetic mean) height of students in Class X to the average height of students in Class Y. This is a great example of a 'concept question', meaning that you don't have to do much math to answer it if you recognize the concept(s) involved.
1) The average height of the students in Class X is 120 centimeters.
Fact 1 gives us the average height for Class X, but tells us nothing about the average height of Class Y.
Fact 1 is INSUFFICIENT
2) The average height of the students in Class X AND Class Y combined is 126 centimeters.
Fact 2 tells us the average height of ALL students, but we have know way to determine the average heights in just Class X or just Class Y.
Fact 2 is INSUFFICIENT
Combined, we know
-The average height of the students in Class X is 120 centimeters.
-The average height of the students in Class X AND Class Y combined is 126 centimeters.
We don't know the NUMBER of students in each class, so the information in Fact 2 will 'skew' based on the number of students in Class X vs. the number in Class Y. For example, if we have an EQUAL number of students in both classes, then the average height for Class Y would be (120+Y)/2 = 126 --> Y = 132 centimeters. However, if the number of students is NOT equal, then the average height of Class Y will change (it could be higher or lower depending on whether Class X had more or less students). Thus, there's no way to determine the exact ratio of the average heights.
Combined, INSUFFICIENT
Final Answer: E
GMAT assassins aren't born, they're made,
Rich