Five integers 2,4,8,10,x. What is the value of x?
1) x not equal to 16
2) Median is equal to mean
70) what is the value of x?
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Hi,
Is it B?
The only way the median is equal to the mean is if the set contains evenly spaced numbers.
Since the set contains all even numbers from 2 to 10, but skips the 6, then X = 6
Is it B?
The only way the median is equal to the mean is if the set contains evenly spaced numbers.
Since the set contains all even numbers from 2 to 10, but skips the 6, then X = 6
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Clearly 1 is not sufficient
form 2
mean =24+x/5
if x<2..median =4hence 4=24+x/5 or x=-4
if x>11..median 8..hence 8=24+x/5 or x=16
since mean=median 24+x must be divisible by 5..hence only possible value of x such that 2<x<10 is x=6 and mean is 6
...all these are possible..hence not sufficient
combining x is either -4 or 6...not sufficient
IMO ans option E
form 2
mean =24+x/5
if x<2..median =4hence 4=24+x/5 or x=-4
if x>11..median 8..hence 8=24+x/5 or x=16
since mean=median 24+x must be divisible by 5..hence only possible value of x such that 2<x<10 is x=6 and mean is 6
...all these are possible..hence not sufficient
combining x is either -4 or 6...not sufficient
IMO ans option E
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vcb wrote:so 6 is a probable answer.. What if x=-4?
The average would then be 4: (-4+2+4+8+10)/5 = 4; The median too would be +4. So we have two different answers. Wat say?
yeah u r correct!! Pick E
If the set is evenly spaced, mean=medianNovember Rain wrote: The only way the median is equal to the mean is if the set contains evenly spaced numbers.
But the reverse is not necessarily true. Example of this is in one of the explanations above. (-4,2,4,8,10) mean=median=4 but the set is not evenly spaced.
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