GMAT PREP
CAN any one suggest the dificulty level of the q and its soln
i cud solve it 5 min
I FEEL LIKE THIS Q IS POSTED IN THE FORUM EARLIER BUT CUD NO
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- thephoenix
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I am not very convinced with the options you gave as all the options are more than 2 pi (which means whole circle)
But here is my approach:
angle (PRO) = 35
since, CR = CP (Radii of same circle) => angle( CRP) = angle (CPR) = 35
hence, angle (PCR)=110
hence, angle (PCO) = 70
hence, angle (CPO) = 70 (alternate angles of parallel lines)
since, CP=CQ (radii) => angle (CPQ)=angle (CQP) = 70
hence, angle (PCQ) = 180 - 70 - 70 = 40
now, 360 --- > 2pi
hence, 40 ----> 2 pi * 40 / 360 = 2 pi / 9
But here is my approach:
angle (PRO) = 35
since, CR = CP (Radii of same circle) => angle( CRP) = angle (CPR) = 35
hence, angle (PCR)=110
hence, angle (PCO) = 70
hence, angle (CPO) = 70 (alternate angles of parallel lines)
since, CP=CQ (radii) => angle (CPQ)=angle (CQP) = 70
hence, angle (PCQ) = 180 - 70 - 70 = 40
now, 360 --- > 2pi
hence, 40 ----> 2 pi * 40 / 360 = 2 pi / 9
- thephoenix
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- Joined: Tue Nov 17, 2009 2:38 am
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pops u have made a slight mistake
360=2 pi r
u have missed it
well thanks for your approach
ans is 2pi
is there any other approach
360=2 pi r
u have missed it
well thanks for your approach
ans is 2pi
is there any other approach
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i think we can also solve it using inner angles in circle.
angle PCO = 2 x angle PRO = 70
similarly, angle QCR = 70
major arc PQ = 180+70+70 = 320
Minor arc PQ = (40 / 360) * 18 pi = 2pi
is this approach correct?
angle PCO = 2 x angle PRO = 70
similarly, angle QCR = 70
major arc PQ = 180+70+70 = 320
Minor arc PQ = (40 / 360) * 18 pi = 2pi
is this approach correct?