For a certain race, 3 teams were allowed to enter 3 members each. A team earned 6 – n points whenever one of its members finished in nth place, where 1 ≤ n ≤ 5. There were no ties, disqualifications, or withdrawals. If no team earned more than 6 points, what is the least possible score a team could have earned?
A. 0
B. 1
C. 2
D. 3
E. 4
Scoretop 14 - Question 7
This topic has expert replies
I do not think that this is the correct solution to the problem because the assumption which you have taken that for least points the team should score 7,8 and 9 position is wrong.
i think you should solve this problem in following way :
Consider three teams to be A, B and C each having three
members...so totally 9 members.
now suppose that 3 persons of Team A come 1st, 2nd and 3rd
then their respective scores will be (6-1)=5, (6-2)=4 and (6-3)=3.
now suppose that Team B has three memebers who came
4th, 5th and 6th...then their respective scores will be
(6-4)=2, (6-5)=1 and 0 (Because n can max be 5).
the team C is supposed to have scored 7th,8th and 9th
positions scoring 0 each.
Adding all the scores together we get:
5+4+3+2+1+0+0+0+0=15
Now the question says no team can score more than 6.
so see if 15 can be divided as 6 6 and some X
X here is the minimum value which we want to determine
yes it is possible
5 and 1
4 and 2
and therefore third team (15-12)=3
so X=3
therefore the answer is 3
!!!
i think you should solve this problem in following way :
Consider three teams to be A, B and C each having three
members...so totally 9 members.
now suppose that 3 persons of Team A come 1st, 2nd and 3rd
then their respective scores will be (6-1)=5, (6-2)=4 and (6-3)=3.
now suppose that Team B has three memebers who came
4th, 5th and 6th...then their respective scores will be
(6-4)=2, (6-5)=1 and 0 (Because n can max be 5).
the team C is supposed to have scored 7th,8th and 9th
positions scoring 0 each.
Adding all the scores together we get:
5+4+3+2+1+0+0+0+0=15
Now the question says no team can score more than 6.
so see if 15 can be divided as 6 6 and some X
X here is the minimum value which we want to determine
yes it is possible
5 and 1
4 and 2
and therefore third team (15-12)=3
so X=3
therefore the answer is 3
!!!