What is the value of y?
(1) 3|x2 – 4| = y – 2
(2) |3 – y| = 11
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ds w/ absolute value
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Option 1 gives you the condition :
y - 2 > 0 or y > 2
Option 2 gives two answers
-8 and 14.
Combining both we get 14.
Hence C
y - 2 > 0 or y > 2
Option 2 gives two answers
-8 and 14.
Combining both we get 14.
Hence C
But mod (x2-4) can be negative when x2 is less than 4 for example when x is =0 or 1, x2-4 may have negative values as well, isn't it??gmatguy16 wrote:but when you combine 1 and 2 you realize that y cannot be negative,it has to be positive..so only only value for y .answer should be c
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mallard906
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