. If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N?
(A) 86
(B) 52
(c)34
d)28
e)10
i am thinking answer is (E). Correct?
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another one
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countingdolls
- Junior | Next Rank: 30 Posts
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- Joined: Mon Oct 02, 2006 7:07 am
No.
(A)
take M as (6n + 1), N as (6n+3).
so, M+N= 2(6n) + 4.
now all you have to do is choose that option which isnt greater than a multiple of 6 by 4.So, 86.
(A)
take M as (6n + 1), N as (6n+3).
so, M+N= 2(6n) + 4.
now all you have to do is choose that option which isnt greater than a multiple of 6 by 4.So, 86.
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anandsebastin
- Junior | Next Rank: 30 Posts
- Posts: 10
- Joined: Fri Oct 13, 2006 9:16 am
I'm afraid not. Answer is A.iamtrying wrote:. If M and N are positive integers that have remainders of 1 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N?
(A) 86
(B) 52
(c)34
d)28
e)10
i am thinking answer is (E). Correct?
M+N = (6x+1)+(6y+3)
=6(x+y)+4
So, all possible values of M+N should satisfy, (M+N) - 4/6 = integer.
Applying this test, you'll see that B,C,D and E satisfy this equation.
As for your conclusion, when you divide 3 by 6, remainder is 3, right?
