X=1/pq. Does the value of X contain an infinite recurring decimal?
(1) p=3^m
(2) q=5^n
138 recurring decimal?
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C for me.
(1) p=3^m -> gives the value of P only. What if q = 3^-m
(2) q=5^n -> gives the value of Q only.
1 & 2 - sufficient
(1) p=3^m -> gives the value of P only. What if q = 3^-m
(2) q=5^n -> gives the value of Q only.
1 & 2 - sufficient
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For me its E.crackgmat007 wrote:C for me.
(1) p=3^m -> gives the value of P only. What if q = 3^-m
(2) q=5^n -> gives the value of Q only.
1 & 2 - sufficient
I can tell you by looking at the problem that its not A or B or D!
Now, what happens when m=n=0? Or m=n= -1 ... Non-recurring.
If m=n=1 ...1/15 which is recurring (0.060606...)
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It should be 'E' as we don't know the value of m and n. m and n could be zero or greater than zero.
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(1)&(2) combinedern5231 wrote:X=1/pq. Does the value of X contain an infinite recurring decimal?
(1) p=3^m
(2) q=5^n
Case a: m=n=0 --> x is not infinite recurring decimal
Case b: m=n=1 --> x is infinite recurring decimal
Answer = E