What is the least number of digits (including repetitions) needed to express 10^100 in decimal notation?
(A) 4
(B) 100
(C) 101
(D) 1,000
(E) 1,001
OA - C
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Decimal notation
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crackgmat007
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ankitns
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The answer is C
Try to find a pattern here....
10^1 = 10 ( 2 digits)
10^2 = 100 (3 digits)
10^3 = 1000 (4 digits)
...
...
We will notice that the number of digits is alwaz 1 + the power that it is raised to.
[spoiler]Hence 10^100 -> 101 digits.[/spoiler]
Hope it helps.
Cheers.
Try to find a pattern here....
10^1 = 10 ( 2 digits)
10^2 = 100 (3 digits)
10^3 = 1000 (4 digits)
...
...
We will notice that the number of digits is alwaz 1 + the power that it is raised to.
[spoiler]Hence 10^100 -> 101 digits.[/spoiler]
Hope it helps.
Cheers.
crackgmat007 wrote:What is the least number of digits (including repetitions) needed to express 10^100 in decimal notation?
(A) 4
(B) 100
(C) 101
(D) 1,000
(E) 1,001
OA - C
Attempt 1: 710, 92% (Q 42, 63%; V 44, 97%)
Attempt 2: Coming soon!
Attempt 2: Coming soon!
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crackgmat007
- Legendary Member
- Posts: 882
- Joined: Fri Feb 20, 2009 2:57 pm
- Thanked: 15 times
- Followed by:1 members
- GMAT Score:690
