Problem Solving

Box W and Box V each contain several blue sticks and red sticks, and all of the red sticks have the same length. The length of each red stick is 19 inches less that the average length of the sticks in Box W and 6 inches greater than the average length of the sticks in Box V. What is the average (arithmetic mean) length, in inches, of the sticks in Box W minus the average length, in inches, of the sticks in Box V?
(A) 3
(B) 6
(C) 12
(D) 18
(E) 24


OA-E

I came up with answer=25. Just need to confirm.

My solving

R+19 =W
R-6 = V

So, W- V =25.

Average length of sticks in Box W=x

Length of each red stick=x-19

Average length of sticks in Box V= x-19-6=x-25

x-(x-25)=25

you're right looks like typo.

Yeah, I made a slight typo at the end there. I'll fix it though

so you guys say, the answer has to be 25 and not 24??

Even I feel the same.
Thanks a lot for discussion