2^(-2x)-2^(-x)-6=0, 2^x=?
soryy dont have answers
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tohellandback
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2^(-2x)-2^(-x)-6=0
1/2^2x - 1/2^x - 6=0
a^2-a-6=0, where a=1/2^x
(a+2)(a-3)=0
a=-2 a=3
1/2^x cannot be equal to -2.
so,
1/2^x=3
2^x=1/3
1/2^2x - 1/2^x - 6=0
a^2-a-6=0, where a=1/2^x
(a+2)(a-3)=0
a=-2 a=3
1/2^x cannot be equal to -2.
so,
1/2^x=3
2^x=1/3
The powers of two are bloody impolite!!
