If each of the 12 teams participating in a certain tournament plays exactly one game with each of the other teams, how many games will be played?
A. 144 B. 132 C. 66 D. 33 E. 23
OA is c
what's a method to tackle this problem?
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12 teams!
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truplayer256
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Team 1 will play 11 games with Team 2-Team 12.
Team 2 will play 10 games with Team 3- Team 12.
Team 3 will play 9 games with Team 4- Team 12.
11+10+9+8+7+6+5+4+3+2+1=66 games.
Team 2 will play 10 games with Team 3- Team 12.
Team 3 will play 9 games with Team 4- Team 12.
11+10+9+8+7+6+5+4+3+2+1=66 games.
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quant-master
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Each team will play with 11 other teams. Hence each team plays 11 games. Hence a total of 11*12 =132 games but since each game involves two teams divide 132/2 = 66fruti_yum wrote:If each of the 12 teams participating in a certain tournament plays exactly one game with each of the other teams, how many games will be played?
A. 144 B. 132 C. 66 D. 33 E. 23
OA is c
what's a method to tackle this problem?
Thanks,
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https://gmat-quants.blocked - My Blog Updated almost daily with new quant fundas. Find collection of quants question in my blog
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shahdevine
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This is a combinations problem where order does not matter. There are 12 teams, and only 2 teams selected to play one another.fruti_yum wrote:If each of the 12 teams participating in a certain tournament plays exactly one game with each of the other teams, how many games will be played?
A. 144 B. 132 C. 66 D. 33 E. 23
OA is c
what's a method to tackle this problem?
C(12,2)
(12x11)/2!=66
You got this!!
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Scott@TargetTestPrep
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The number of games played is 12C2 = 12! / (2! x 10!) = (12 x 11) / 2 = 66.
Answer: C
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