OA coming after some people try answering..
Matt starts a new job, with the goal of doubling his old average commission of $400. He takes a 10% commission, making commissions of $100.00, $200.00, $250.00, $700.00, and $1,000 on his first 5 sales. If Matt made two sales on the last day of the week, how much would Matt have had to sell in order to meet his goal?
Difficult Math Problem #17
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Hey!!! this is the way u do it :
he wants to dowble his commission from $400 to $800
100+200+250+700+1000+x+y
---------------------------------------- = 800
7
i.e 2250+x+y = 5600
x+y = 3350
Now he has to sell
10/100 * z = 3350
z= 33500
He has to sell 33500 in order to double his average
he wants to dowble his commission from $400 to $800
100+200+250+700+1000+x+y
---------------------------------------- = 800
7
i.e 2250+x+y = 5600
x+y = 3350
Now he has to sell
10/100 * z = 3350
z= 33500
He has to sell 33500 in order to double his average
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- Senior | Next Rank: 100 Posts
- Posts: 34
- Joined: Sun Sep 03, 2006 6:00 am
The asnwer is correct if we assume that he sells during seven days. However, it could also be the case that there are only 5 days. Note that problem stated that he made five sales during the the week and 2 sales on the last day of the week.
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Assuming the two sales on Matt's last day of the week must total $33,500.
(100 + 200 + 250 + 700 + 1000 + x) / 7 = 800
2250+ x = 5600
x= 5600-2250
x = 3350
since x which is the 10% Matt's commission, then the sale is $33,500.
(100 + 200 + 250 + 700 + 1000 + x) / 7 = 800
2250+ x = 5600
x= 5600-2250
x = 3350
since x which is the 10% Matt's commission, then the sale is $33,500.