probability
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For the sum to be odd, the three balls must be odd,odd,odd, or even,even,odd, or even, odd, even, or odd, even, even
The probability of each case is 1/8 ( 1/2 * 1/2 * 1/2).
Then total probability is 4 * 1/8 = 1/2
The probability of each case is 1/8 ( 1/2 * 1/2 * 1/2).
Then total probability is 4 * 1/8 = 1/2
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Alternatively: it doesn't matter what your first two selections are. They either add to an even number, in which case you need the third ball to be odd (probability 1/2) or they add to an odd number, in which case you need the third ball to be even (probability 1/2). No matter what the situation after your first two selections, there's a 1/2 probability you'll arrive at an odd sum after your third selection.
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Yup, I arrived at the solution the same way Ian did. Probability of any ball being odd is same of that being even. And the total sum can be only either even or odd. Hence, there is no preference for even or odd. Hence both are equally likely. Exhaustive set. Hence, 1/2 for each.