Robert can eat a 20 kg bag of potatoes in 10 days. If together with his wife, Jane, they can eat the same bag in 7 days, how many days does it take Jane to eat a 20 kg bag of potatoes by herself?
1. 46 2/3
2. 23 1/3
3. 17
4. 12
5. 11 2/3
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eating potatoes
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ssmiles08
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IMO B.
If Rob can eat 20 kg in 10 days, he can eat 2kg in 1 day (20/10)
in 7 days Rob can eat 7*2 kg = 14 kg of potatoes.
which means Jane takes in 6kg of potatoes in 7 days.
Rate of Jane is 6/7
20 kg = amount. SO amount/rate = days
20*(7/6) = 70/3 ~ 23 1/3 (B)
If Rob can eat 20 kg in 10 days, he can eat 2kg in 1 day (20/10)
in 7 days Rob can eat 7*2 kg = 14 kg of potatoes.
which means Jane takes in 6kg of potatoes in 7 days.
Rate of Jane is 6/7
20 kg = amount. SO amount/rate = days
20*(7/6) = 70/3 ~ 23 1/3 (B)
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truplayer256
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Rob eats 2 kg of potatoes per day and Jane eats x kg of potatoes per day. We know that when Jane and Rob's rates are combined, they can finish the bag of 20 kg potatoes in 7 days, so:
7(2+x)=20
14+7x=20
x=6/7
So Jane can eat 6/7 kg of potatoes per day, and it'll take her (20)/(6/7) or 70/3 days to eat 20 kg of potatoes. B is the correct answer.
7(2+x)=20
14+7x=20
x=6/7
So Jane can eat 6/7 kg of potatoes per day, and it'll take her (20)/(6/7) or 70/3 days to eat 20 kg of potatoes. B is the correct answer.
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bluementor
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x = number days Jane alone takes to finish eating the potatoes.
1/x + 1/10 = 1/7
1/x = (10 - 7)/70
x = 70/3 = 23 1/3
Choose B.
-BM-
1/x + 1/10 = 1/7
1/x = (10 - 7)/70
x = 70/3 = 23 1/3
Choose B.
-BM-
