Triangle T
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I don't understand what the 1st sentence is saying.
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- ssmiles08
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IMO A.
If you draw out a triangle with base at (0,0) and (6,0), the avg of the those two points is the x co-ordinate of the center.
in this case, the center point of which is (3,2) has the x co-ordinate of 3.
halfway between the base is 3.
2 is the y co-ordinate for the center which means it must be halfway in between 0 and 4.
so the height is (3,4)
what is the OA?
If you draw out a triangle with base at (0,0) and (6,0), the avg of the those two points is the x co-ordinate of the center.
in this case, the center point of which is (3,2) has the x co-ordinate of 3.
halfway between the base is 3.
2 is the y co-ordinate for the center which means it must be halfway in between 0 and 4.
so the height is (3,4)
what is the OA?
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It should be (3,6). It is asking coordinate of the other third vertex.
Xcenter = avg of the x coords of T
Ycenter= avg of the y coords of T
(x1+x2+x3)/3=3=> x3=3
similarly
(y1+y2+y3)/3=2=> y3=6
(3,6)
Xcenter = avg of the x coords of T
Ycenter= avg of the y coords of T
(x1+x2+x3)/3=3=> x3=3
similarly
(y1+y2+y3)/3=2=> y3=6
(3,6)
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rah_pandey wrote:It should be (3,6). It is asking coordinate of the other third vertex.
Xcenter = avg of the x coords of T
Ycenter= avg of the y coords of T
(x1+x2+x3)/3=3=> x3=3
similarly
(y1+y2+y3)/3=2=> y3=6
(3,6)
rah_pandey, you're right! OA is (3,6)