Here is a problem from a GMAT prep test I took earlier today. The answer I picked is wrong. ANY HELP WILL BE APPRECIATED.
OA after a few replies.
GMATPREP HARD PS QUESTION!!
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- givemeanid
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- givemeanid
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- Joined: Sun Jun 17, 2007 2:51 pm
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Draw a line segment PR where R is on the X axis and PR is perpendicular to X axis.
Now, PRO is a right triangle with PR = 1 and OR = sqrt(3)
OP = sqrt(PR^2 + OR^2) = sqrt(1+3) = 2.
This is a 30-69-90 triangle (its a right triangle with ratios of sides as 1:sqrt3:2)
Angle POR = 30 (since it's opposite to side of length 1 in the above mentioned triangle).
Now, draw a line segment QT where T is on the X axis and QT is perpendicular to X axis.
POR + POQ + QOT = 180 (they form a straight line)
30 + 90 + QOT = 180
QOT = 60
In triangle OQT, QOT = 60, QTO = 90. So, OQT = 30
Also, OP = OQ = 2 (radius of the circle)
So, again from the 30-60-90 triangle property, since OQ = 2, OT = 1 and TQ = sqrt(3).
Hence s = 1.
Now, PRO is a right triangle with PR = 1 and OR = sqrt(3)
OP = sqrt(PR^2 + OR^2) = sqrt(1+3) = 2.
This is a 30-69-90 triangle (its a right triangle with ratios of sides as 1:sqrt3:2)
Angle POR = 30 (since it's opposite to side of length 1 in the above mentioned triangle).
Now, draw a line segment QT where T is on the X axis and QT is perpendicular to X axis.
POR + POQ + QOT = 180 (they form a straight line)
30 + 90 + QOT = 180
QOT = 60
In triangle OQT, QOT = 60, QTO = 90. So, OQT = 30
Also, OP = OQ = 2 (radius of the circle)
So, again from the 30-60-90 triangle property, since OQ = 2, OT = 1 and TQ = sqrt(3).
Hence s = 1.
So It Goes