gmat prep

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gmat prep

by sneakpeek » Wed Jun 27, 2007 4:47 pm
rate of chemical reaction
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by jayhawk2001 » Wed Jun 27, 2007 8:52 pm
R = rate, Ca = conc of chemical A, Cb = conc of chemical B
Let K be a constant.

We have, R = K * Ca^2 / Cb

If Cb becomes 2*Cb, we are asked to find out how Ca should change to
keep R the same. We know K is a constant.

K * Ca^2 / Cb = K* x *Ca^2 / 2*Cb

Solving for x, we get sqrt(2) i.e. 1.414

So, Ca should be increased by 41.4%

Hence D