DS question

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DS question

by dunkin77 » Sun Jun 10, 2007 9:27 am
x>0?
(1)|x|>x^2
(2)x<|x^1|



the answer seems to be C but,

from 1), we only know the x is either 0<x<1 or -1<x<0.....


Can anyone guide me?

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Re: DS question

by jayhawk2001 » Sun Jun 10, 2007 10:21 am
dunkin77 wrote:x>0?
(1)|x|>x^2
(2)x<|x^1|
Hmm, from (2), we know x < |x| i.e. x < 0. Why is (2) alone not sufficient ?

Yeah, 1 tells us 0<x<1 (or) -1<x<0. insufficient.