x>0?
(1)|x|>x^2
(2)x<|x^1|
the answer seems to be C but,
from 1), we only know the x is either 0<x<1 or -1<x<0.....
Can anyone guide me?
DS question
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- jayhawk2001
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Hmm, from (2), we know x < |x| i.e. x < 0. Why is (2) alone not sufficient ?dunkin77 wrote:x>0?
(1)|x|>x^2
(2)x<|x^1|
Yeah, 1 tells us 0<x<1 (or) -1<x<0. insufficient.