xy plane

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xy plane

by mariah » Fri Jan 23, 2009 1:31 pm
26.In the xy-plane, the graph represented by y=x^2+px+r have how many intersects with axis-x?
1). p^2>r
2). r^2>p

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by DanaJ » Fri Jan 23, 2009 2:19 pm
An intersection with axis X is the equivalent of y = x^2+px+r = 0. This is a second degree equation, which could have from 0 to maximum two roots, depending on the discriminant, which will be p^2 - 4r.

Let me explain from the top with equations so that you may understand a bit better.
Second degree equations have the following pattern: a*x^2 + b*x + c = 0. The discriminant for these equations is called delta and is equal to b^2 - 4ac. Delta helps you to figure out how many solutions there are to your equation, meaning how many x-es fulfill a*x^2 + b*x + c = 0. You have three cases:

1. delta < 0 means that there is no x with a*x^2 + b*x + c = 0. Example: x^2 + 2x + 6 = 0 (in this case, the equation will always be positive).
2. delta = 0 means that there is just one x with a*x^2 + b*x + c = 0. Example: x^2 + 2x + 1 =0 (equivalent to (x+1)^2 = 0, giving you x = -1)
3. delta > 0 means that there are two x'es with a*x^2 + b*x + c = 0. Example: x^2 -6x +8 = 0 (equivalent to (x-4)(x-2) = 0, with x either 4 or 2).

Now let's get back to our problem.... We need to figure out if p^2 - 4r is smaller, greater than or equal to 0.
Stmt 1 doesn't shed light on whether p^2 is greater than 4r, just on whether p^2 is greater than r. So it is not sufficient by itself.
Stmt 2 is again insufficient by itself, largely for the same reason: you do not know the relationship between p^2 and 4r.

The two statements taken together do not help much either.

So my guess is E... Hope I'm not wrong, seeing as how my explanation is so long...

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lol

by yvichman » Sat Jan 24, 2009 9:32 am
Dana this is sooo over my head its not even funny. If I get a question like this on the GMAT, I'm playing the guessing game and moving on. I can't afford to waste more than 10 seconds on this type of question that I will ultimately get wrong anyway.

I'm assuming
A) you have an excllent math background
B) are much brighter than I
C) I'm just an idiot
D) all of the above

In all seriousness, whats your math background?

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by DanaJ » Sat Jan 24, 2009 10:37 am
Well it's nothing impressive, I suppose... Just your average sciences high school and college - finance is my major... I'm no rocket scientist, that's for sure... Just that, here, in Romania, they force feed us math... I for one learned in the 9th grade what a friend of mine was learning in college. But don't get me wrong, a lot of people can't keep up... I'm just one of the lucky ones who did...

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by DanaJ » Sun Jan 25, 2009 7:11 am
yvichman: Oh and I forgot - don't ever say that you are an idiot! That is most certainly not true... I guarantee that if I were to sit next to you for half an hour and explain second degree equations using examples you'd master them!

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by mariah » Sat Feb 07, 2009 3:38 pm
oa E