I appreciate all the help I have got on this forum.
A couple more questions to solve.
GMAT prep - a couple more
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Free selection of 3 apples without conditions = 10C3 = 120
Selection of 2 red apples and 1 green apple = 7C2 * 3C1 = 21*3 = 63
Hence probability = 63/120 = 21/40
Selection of 2 red apples and 1 green apple = 7C2 * 3C1 = 21*3 = 63
Hence probability = 63/120 = 21/40